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mamaluj [8]
2 years ago
10

Anyone know how to do this?

Chemistry
1 answer:
alex41 [277]2 years ago
8 0

Answer:

2X₂Y₃    →     4X     +     3Y₂

Explanation:

This problem is about balancing chemical equations.

The reaction is given as:

          X₂Y₃    →     X     +     Y₂

To balance the reaction equation, we use a mathematical approach.

      aX₂Y₃    →     bX     +     cY₂

Conserving X;   2a  = b

                    Y;   3a = 2c

Now, let us make a  = 1

                              b  = 2

                              c  = \frac{3}{2}  

Multiply through by 2;

         a  = 2, b  = 4 , c  = 3;

        2X₂Y₃    →     4X     +     3Y₂

 

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You need a 70% alcohol solution. On hand, you have a 135 mL of a 20% alcohol mixture. You also have 85% alcohol mixture. How muc
frutty [35]

To obtain the desired solution:

450 mL of 85% alcohol solution is needed to obtain the desired solution.  

Calculation:

Let x be the amount of the 85% alcohol required

The volume of the resulting 70% alcohol solution will then be = x + 135 ml

135 mL of the 20% alcohol solution contains the amount of "pure" alcohol is =  0.20×135 mL.

The 85% alcohol solution contains x mL of "pure" alcohol = 0.85× x mL.

The total amount of the "pure" alcohol is the sum

=  0.20×135 + 0.85× x mL.

It should be equal to the amount of the "pure" alcohol in the mixture, which is = 0.70× (x+135) ml.

So, your "pure alcohol" equation is,  

=  0.85× x + 0.20×135 = 0.70× (x+135)

Simplify and solve it for x:

0.85x + 0.20×135 = 0.70x + 0.70×135,

0.85x - 0.70x = 0.70×135 - 0.20×135,

0.15x = 67.5

x = 67.5/0.15

= 450mL.

Learn more about the alcohol solution here,

brainly.com/question/12246176

#SPJ4

 

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