The question is incomplete, here is the complete question:
Consider the reaction
Initially,
= 3.60 M; at equilibrium
. Calculate the equilibrium concentration for 
<u>Answer:</u> The equilibrium concentration of ammonia is 2.8 M
<u>Explanation:</u>
We are given:
Initial concentration of
= 3.60 M
Initial concentration of
= 3.60 M
For the given chemical equation:

Initial: 3.60 3.60
At eqllm: 3.60-4x 3.60-7x 2x 6x
We are given:
Equilibrium concentration of
= 0.60 M
Evaluating the value of 'x'

So, equilibrium concentration of 
Hence, the equilibrium concentration of ammonia is 2.8 M