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Lostsunrise [7]
3 years ago
11

Elida will use six different wires for a science project.These fractions represent the diameters of these wires in inches. Which

list shows the diameters of the wires in order from least to greatest

Mathematics
2 answers:
Ivanshal [37]3 years ago
5 0

Answer:

The answer is G

Step-by-step explanation:

Also, you say this is high school work but I'm doing this in 6th grade

Semmy [17]3 years ago
5 0

Answer:

g aka b

Step-by-step i really dont

have one but

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Question 3<br> BESED<br> what is the slope?<br> (-7,-4) (-14, 3)
Nadya [2.5K]

Slope= (Y2-Y1)/(X2-X1)

Slope=(3-(-4) ) /(-14-(-7) )

Slope= (3+4)/(-14+7)

Slope=7/-7

Slope= -1

6 0
3 years ago
The confidence interval is reported as follows: Lower 95% CI &lt; p &lt; Upper 95% CI For this question you will be calculating
monitta

Answer:

lower 95% Cl is 0.292

Step-by-step explanation:

p^ = 0.4783

n = 23

for 95% Cl,

z = 1.9600

Inputting all the available data into P as attached below

LCL = 0.292

UCL = 0.670

therefore, lower 95% Cl = 0.292

7 0
3 years ago
Louisa wants to buy an online movie subscription that is on sale for 15% off. She writes the expression c − 0.15c to represent t
Tpy6a [65]

Answer:

#UseSimplifiedExpression

Step-by-step explanation:

6 0
3 years ago
2x^2+3x-2, a=0 How do I find the derivative?
Ghella [55]

You can use the definition:

\displaystyle f'(x) = \lim_{h\to0}\frac{f(x+h)-f(x)}h

Then if

f(x) = 2x^2+3x-2

we have

f(x+h) = 2(x+h)^2+3(x+h) - 2 = 2x^2 + 4xh+2h^2+3x+3h-2

Then the derivative is

\displaystyle f'(x) = \lim_{h\to0}\frac{(2x^2+4xh+2h^2+3x+3h-2)-(2x^2+3x-2)}h \\\\ f'(x) = \lim_{h\to0}\frac{4xh+2h^2+3h}h \\\\ f'(x) = \lim_{h\to0}(4x+2h+3) = \boxed{4x+3}

I'm guessing the second part of the question asks you to find the tangent line to <em>f(x)</em> at the point <em>a</em> = 0. The slope of the tangent line to this point is

f'(0) = 4(0) + 3 = 3

and when <em>a</em> = 0, we have <em>f(a)</em> = <em>f</em> (0) = -2, so the graph of <em>f(x)</em> passes through the point (0, -2).

Use the point-slope formula to get the equation of the tangent line:

<em>y</em> - (-2) = 3 (<em>x</em> - 0)

<em>y</em> + 2 = 3<em>x</em>

<em>y</em> = 3<em>x</em> - 2

5 0
3 years ago
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