Discount = 365*30/100 = $109.5
sales price = 365*70/100 = $255.5
Did you understand?
For a triangle to be a triangle all the angles have to add up to 180 degrees. So 52 degrees plus 28 degrees would equal 80. So now to find the answer 180 - 80 then your final answer is 100! Hope This Helps
Use the law of sines....(sina/A=sinb/B=sinc/C for any triangle)
What that means is the sine of an angle divided by the length of the side opposite the angle is a ratio that is true each angle/side pair...In this case:
sin90/122=sinc/22 rearrange to solve for sinc
sinc=(22sin90)/122 now take the arcsin to solve for c
c=arcsin[(22sin90)/122]
c≈10.388857815469611987441020361405
c≈10.39° (to nearest hundredth of a degree)
Answer:
176 square yards
Step-by-step explanation:
<u><em>The picture of the question in the attached figure N 1</em></u>
we know that
The area of the walkway around the rectangular pool, is equal to the area of two trapezoids (#1 and #2), plus the area of two smaller rectangles (#3 and #4)
see the attached figure N 2 to better understand the problem
step 1
Find the area of the two trapezoids (#1 and #2)
![A=2[\frac{1}{2}(b_1+b_2)h]](https://tex.z-dn.net/?f=A%3D2%5B%5Cfrac%7B1%7D%7B2%7D%28b_1%2Bb_2%29h%5D)
simplify
we have
substitute
step 2
Find the area of the two smaller rectangles (#3 and #4)
![A=2[LW]](https://tex.z-dn.net/?f=A%3D2%5BLW%5D)
we have
substitute
![A=2[(4)(6)]=48\ yd^2](https://tex.z-dn.net/?f=A%3D2%5B%284%29%286%29%5D%3D48%5C%20yd%5E2)
step 3
Find the area of the walkway around the rectangular pool
32.8 feet because the answer is that and that answer is correct
