Answer:
-2/3 or 2/-3 ( either one is correct)
Step-by-step explanation:
1. Pick one the points to start with
2. Move either three to the left (if you are starting with x) or move down twice (if you are starting with y)
3. Move up twice (if starting with x) or move three to the right (if starting with y)
4. write the answer with the y at the top and x on the bottom
9514 1404 393
Answer:
(b) tan B = 8/6
Step-by-step explanation:
The mnemonic SOH CAH TOA is intended to remind you of the relevant relationships:
Cos = Adjacent/Hypotenuse
Tan = Opposite/Adjacent
Then angle B is involved in tangent and cosine relationships this way:
tan B = 8/6 . . . . . . matches 2nd choice
cos B = 6/10 . . . . . matches no choices
_____
<em>Additional comment</em>
Both of the offered cosine choices give a cosine value that is greater than 1. The cosine of a real angle is never greater than 1, so those can be rejected immediately.
Answer:
1.3c - 4.69
Step-by-step explanation:
5.2 - 3.9 = 1.3
2.65 - 7.35 = -4.69
The answer is B, 240 is divisible by 3,4,5 and 8.
Nitrogen (N) has a molar mass of about 14.007 g/mol, so you have
100.0 g N₂ = (100.0 g) • (1/28.014 mol/g) ≈ 3.570 mol N₂
Hydrogen (H) has a molar mass of about 1.008 g/mol, so
100.0 g H₂ = (100.0 g) • (1/2.016 mol/g) ≈ 49.60 mol H₂
In the balanced reaction, 1 mole of N₂ reacts with 3 moles of H₂ to make 2 moles of NH₃. We have
3.570 • 3 ≈ 10.71
so the reaction would use up all 3.570 mol N₂ and 10.71 mol H₂ to produce about 7.139 mol NH₃.
(A) H₂ is the excess reactant. There is an excess of 49.60 - 10.71 ≈ 38.89 mol H₂.
(B) N₂ is the limiting reactant. All of the N₂ gets consumed in the reaction.
(C) NH₃ has a molar mass of (14.007 + 3 • 1.008) g/mol = 17.031 g/mol. This reaction would theoretically yield about 7.139 mol NH₃, or
7.139 mol NH₃ = (7.139 mol) • (17.031 g/mol) ≈ 121.6 g NH₃
