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Otrada [13]
3 years ago
7

The point (5,6) is the solution to which of the following systems of equations

Mathematics
1 answer:
VikaD [51]3 years ago
3 0

Answer:

i dont know

Step-by-step explanation:

e

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WILL MARK BRAINLIEST!! EASY 25 POINTS!! DUE IN 20 MINUTES!!
vfiekz [6]

Answer:

  • C. 4

Step-by-step explanation:

<u>Given function:</u>

  • y = 5x² – 20x + 24

<u>Convert the equation into vertex form:</u>

  • y = 5x² - 20x + 20 + 4 =
  •      5(x² - 4x + 4) + 4 =
  •      5(x - 2)² + 4

Vertex is (2, 4) at which the minimum y-value is 4

Correct choice is C

3 0
3 years ago
In our class, there are 14 female and 11 male students. a. Pick one student randomly, what is the probability you get a female s
Reika [66]

Answer:

a) 56% probability you get a female student.

b) 30.33% probability that both are female

c) 43.52% probability that you get 2 female and one male

d) 18.26% probability that you get 1 female and 3 male

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in whih the students are chosen is not important. So we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

a. Pick one student randomly, what is the probability you get a female student?

Desired outcomes:

1 female student from a set of 14. So

D = C_{14,1} = \frac{14!}{1!13!} = 14

Total outcomes:

1 student from a set of 25. So

T = C_{25,1} = \frac{25!}{1!24!} = 25

Probability:

P = \frac{D}{T} = \frac{14}{25} = 0.56

56% probability you get a female student.

b. Pick two students randomly, what is the probability that both are female?

Desired outcomes:

2 female students, from a set of 14. So

D = C_{14,2} = \frac{14!}{2!12!} = 91

Total outcomes:

2 students from a set of 25. So

T = C_{25,2} = \frac{25!}{2!23!} = 300

Probability:

P = \frac{D}{T} = \frac{91}{300} = 0.3033

30.33% probability that both are female

c. Pick three students randomly, what is the probability that you get 2 female and one male?

Desired outcomes:

2 female students, from a set of 14, and one male student, from a set of 11. So

D = C_{14,2}*C_{11,1} = \frac{14!}{2!12!}*\frac{11!}{1!10!} = 1001

Total outcomes:

3 students from a set of 25. So

T = C_{25,3} = \frac{25!}{3!22!} = 2300

Probability:

P = \frac{D}{T} = \frac{1001}{2300} = 0.4352

43.52% probability that you get 2 female and one male

d. Pick four students randomly, what is the probability that you get 1 female and 3 male?

Desired outcomes:

1 female student, from a set of 14, and 3 male students, from a set of 11.

D = C_{14,1}*C_{11,3} = \frac{14!}{1!13!}*\frac{11!}{8!3!} = 2310

Total outcomes:

4 students from a set of 25. So

T = C_{25,4} = \frac{25!}{4!21!} = 12650

Probability:

P = \frac{D}{T} = \frac{2310}{12650} = 0.1826

18.26% probability that you get 1 female and 3 male

5 0
3 years ago
Pls help me with this question
allochka39001 [22]

Answer:

Step-by-step explanation:

For the first question the answer is 50(0.2 + 1)^2 = 72

For the second question it is y = 32

Step-by-step explanation:

In case you need to see how i got it...it's below

For number 1, y is proportional to (x + 1)^2

The equation would be y(x +1)^2 = k(the constant). Then I substituted numbers you gave me in the equation which was : 50(0.2 + 1)^2 = k(72)

For number 2 I used this equation: y (x + 1)^2 = 72. I substituted x for 0.5. The equation will be: y(0.5 + 1)^2 = 72. Then I got 32 for y.

Hope this helps:) i am the best lil kissman

3 0
3 years ago
please help me i’m so scared idk how to do math i’m going to fail this test i cannot afford to fail please brainly friends pleas
Nataly [62]

Answer:

The answer is A

Step-by-step explanation

7 0
3 years ago
Find the total surface area of the following cone. Leave your answer in terms of Pi. 4cm 3cm
castortr0y [4]

The triangle formed from the height of the cone and the radius of its base is a special 3,4,5 triangle. The slant height is 5cm.

Recall that the area of a circle = pi*r^2

Substitute 3 in for r

Area = pi * (3)^2 = 9pi

SA = pi*r*l + B

Substitute our values into the equation

SA = pi * 3 * 5 + 9pi

SA = 15pi + 9pi

SA = 24pi cm^2

5 0
3 years ago
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