The point (5,6) is the solution to which of the following systems of equations

5x + 5x =10x____^a0

PSYCHO15rus [73]

5(x + 10)? A.5x + 10 B.5x + 10x C.5x + 50 D.5 + x + 10.

7 0

3 years ago

Geometry thing help<br>aa

irina [24]

Answer:

Step-by-step explanation:

Since we know that the two lines are parallel because of alternate interior angles (5x-20)=3x

then solve for x

5x-20=3x

-20=-2x

x=10°

5 0

2 years ago

Read 2 more answers

The number of subsets that can be created from the set {1, 2, 3} is:

kkurt [141]

Answer:3

Step-by-step explanation:

7 0

2 years ago

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Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?

likoan [24]

$\mathrm{Use\:the\:rational\:root\:theorem}$

$a_0=15,\:\quad a_n=2$

$\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:3,\:5,\:15,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\:2$

$\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:3,\:5,\:15}{1,\:2}$

$-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3$

$\mathrm{Compute\:}\frac{2x^3-5x^2-28x+15}{x+3}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }2x^2-11x+5$

$=\left(x+3\right)\left(2x^2-11x+5\right)$

$Factor: 2x^2-11x+5$

$2x^2-11x+5=\left(2x^2-x\right)+\left(-10x+5\right)$

$=x\left(2x-1\right)-5\left(2x-1\right)$

$2x^3-5x^2-28x+15=\left(x+3\right)\left(x-5\right)\left(2x-1\right)$

$\left(x+3\right)\left(x-5\right)\left(2x-1\right)=0$

$\mathrm{Using\:the\:Zero\:Factor\:Principle:}$

thus zeros of f(x) is

$x=-3,\:x=5,\:x=\frac{1}{2}$

5 0

2 years ago

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What is an equation of the line that passes through

lys-0071 [83]

Answer:

B

Step-by-step explanation:

For the perpendicular of an equation you need to flip the fraction and change the sign from positive to negative or if it's negative to positive. 3/2 is changed to -2/3 which when multiplied by -2 gives you 4/3 and 4/3+5/3 is equal to 3.

3 0

2 years ago