Answer:
yes they are
Step-by-step explanation:
Answer:
The area of this shape equals 
Step-by-step explanation:
From the diagram, we can see that this shape is a parallelogram (since opposite sides are equal to each other). The formula for the area of the parallerlogram is as follows:
(where "b" is the base, and "h" is the height).
And so we get...

Assuming you want to find x?
You know that the angles at C and B have to be the same (6x) because it’s an isosceles triangle (as indicated by the lines going through AC and AB), and angles in a triangle add to 180*
So 3x + 6x + 6x = 180*
15x = 180*
x = 180*/15
x = 12*
Sec(theta) = 1 / cos (theta) = hypotenuse / x -coordinate
hypotenuse = 1 (because it is the radius of the unit circle)
sec (theta) = 1 / (-3/5) = - 5/3
cot (theta) = 1 / tan(theta) = x-coordinate / y - coordinate
cot (theta) = -3/5 / y
y^2 + (-3/5)^2 = 1 => y^2 = 1 - 9/25 = 16/25 = y = +/- 4/5
Third quadrant => y = -4/5
=> cot (theta) = (-3/5) / (-4/5) = 3/4
20+(-3.05)+(-9.8)=20-3.05-9.8=7.15