We are asked to determine the area of the given figure. To do that we will divide the figure into a square and a triangle. The area of the square is the product of its dimension, therefore, the area is:

$A_{sq}=mp$

The area of the triangle is given by the following formula:

$A_t=\frac{bh}{2}$

Where "b" is the base and "h" is its height. Replacing the values:

$A_t=\frac{(6)(m)}{2}=\frac{1}{2}6m$

The total area is the sum of both areas:

$A=A_{sq}+A_t$

replacing the areas:

$A=mp+\frac{1}{2}6m$

7 0

1 year ago

What is the slope of the line passing through the points (0, −5) and (4, 2)?

liraira [26]

$(0,-5) \\
x_1=0 \\ y_1=-5 \\ \\
(4,2) \\
x_2=4 \\ y_2=2 \\ \\
\hbox{the slope } = \frac{y_2-y_1}{x_2-x_1}=\frac{2-(-5)}{4-0}=\frac{2+5}{4}=\frac{7}{4}$

The slope is 7/4.

8 0

3 years ago

Read 2 more answers

3. The line y - 6 = (x - 3) passes through which point?

Karolina [17]

Answer:

answer is ya mum

Step-by-step explanation:

8 0

2 years ago