I just happened to notice that 32 is incorrect, it should be A
33. (21x+14)/5y+4y*5y/7(3x+2)
((21x+14)*5y)/((9y*7(3x+2)
((5(21x+14)/63(3x+2)
35(3x+2)/63(3x+2)
5/9 is the answer
37. |-3--7|+|-7--3|
|-3+7|+|-7+3|
|4|+|-4|
4+4=8
8 is the correct answer
38. 99999/1 you can 99999
Answer:
Tuesday or Wednesday
Step-by-step explanation:
I looked at a calendar.
Factorise the 5
5m + 5n = 5(m+n)
Answer:
(2,1)
Step-by-step explanation:
X=2 and y=1
The smaller of 2 consecutive integers is -15. The equation to determine the consecutive integers is x + (x + 1) = -29
<u>Solution:</u>
Given that sum of two consecutive integer is -29.
Need to write the equation and determine the smaller of 2 consecutive integers.
Let’s smaller integer be represented by variable x
So bigger consecutive integer will be represented by x + 1
As sum of two integer = -29
=> x + (x + 1) = -29
=> 2x + 1 = -29
=> 2x + 30 = 0 ----------(1)
On solving equation (1) for x we get
2x =-30
=> x = -15
Smallest integer = x = -15
Bigger integer = x + 1 = -15 + 1 = -14
Hence required smaller integer = -15 and required equation is x + (x + 1) = -29
