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MaRussiya [10]
3 years ago
5

Here is a situation: I have $5. I save $2 each week. How many weeks do I need to save until I have at least $50? Write the inequ

ality for this situation and solve it. Discuss the meaning of your solution.
Mathematics
2 answers:
kompoz [17]3 years ago
6 0

Answer:

22 Weeks

Step-by-step explanation:

You just divide 50 by 2 to get 25 and it will take you 3 weeks to get the equivalent of 5 dollars therefore you subtract 3 from 25 and get 22, meaning that it will take 22 Weeks for you to save at least $50. The meaning of my solution is that I just used basic division addition and subtraction to find my answer.

Oksana_A [137]3 years ago
6 0

Answer:

1.  it will take you 22.5 weeks or 23 if you are supposed to round it

2. 5+2x>50

Step-by-step explanation:

i calculated it.

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Step-by-step explanation:

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There are 2 sandwiches, 6 drinks, and 1 dessert to choose from. How many lunch specials are possible?
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I think that would be 9
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Write an equation of the line passing through the point (-10,3) that is parallel to the line 5x+2y=12
dangina [55]

y= (-5/2)x - 22

because 5x+2y=12 turns to y=(-5/2)x + 6 and the line parallel to it has to have the same slope so you have to just get the y intercept by plugging in -10 into the equation (-5/2)(-10)+?=3 and ?= -22.

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3 years ago
Sixty-five randomly selected car salespersons were asked the number of cars they generally sell in one week. Fourteen people ans
Bond [772]

If Sixty-five randomly selected car salespersons were asked the number of cars they generally sell in one week. Then the mean of the sample is 3.75.

<h3>What is Mean?</h3>

The average of a group of numbers is simply defined as the mean. In statistics, the mean is regarded as one of the indicators of central tendency.

Sixty-five randomly selected car salespersons were asked the number of cars they generally sell in one week.

Fourteen people answered that they generally sell two cars; nineteen generally sell three cars; twelve generally sell four cars; nine generally sell five cars; eleven generally sell six cars.

Then the mean of the sample will be

\rm Mean = \dfrac{1}{N} \times \Sigma _{i}   \ \ x_if_i

Then the table is given below.

Then we have

\rm Mean = \dfrac{1}{65} \times (244)\\\\\\Mean = 3.7538\\\\Mean \approx 3.75

More about the mean link is given below.

brainly.com/question/521501

#SPJ1

5 0
2 years ago
when the polynomial f(x) is divided by (x-2) the remainder is 4, and when it is divided by (x-3) the remainder is 7. Given that
natima [27]

f(x)=(x-2)(x-3)Q(x)+ax+b

Recall the polynomial remainder theorem: the remainder upon dividing a polynomial p(x) by x-c is equal to p(c). This means that f(2)=4 and f(3)=7, which tell us

4=2a+b

7=3a+b

From here we can solve for a,b:

4=2a+b\implies b=4-2a

7=3a+b=3a+(4-2a)\implies a=3\implies b=-2

so that

f(x)=(x-2)(x-3)Q(x)+3x-2

Now,

\dfrac{f(x)}{(x-2)(x-3)}=Q(x)+\dfrac{3x-2}{(x-2)(x-3)}

so the remainder upon dividing f(x) by (x-2)(x-3) is 3x-2.

Next, if f is a cubic function, then Q(x) is a linear polynomial that can be written as Q(x)=cx-d. The coefficient of x^3 in f(x) is 1 (unity), so that expanding f(x) gives us

f(x)=(x-2)(x-3)(cx-d)+3x-2

f(x)=(cx^3-(5c+d)x^2+(6c+5d)x-6d)+3x-2

f(x)=cx^3-(5c+d)x^2+(6c+5d+3)x-(6d+2)

\implies c=1

and we also have that f(1)=1, so that

1=1-(5+d)+(6+5d+3)-(6d+2)

\implies2d=2\implies d=1

so that

Q(x)=x-1

4 0
3 years ago
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