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Elenna [48]
3 years ago
14

What is the volume of this rectangular prism? 3 cm DI cm 1 cm 2 Y

Mathematics
2 answers:
TiliK225 [7]3 years ago
5 0

Answer:

3/4 cm^3

Step-by-step explanation:

Volume = base area * height. Where base area is 1/2*1/2 (As it is a square) and height = 3 cm, so times together get 3/4.

Olegator [25]3 years ago
5 0

Step-by-step explanation:

multiply them all

V=h×l×w

V=½cm × 3cm × ½cm

V=¾cm³

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SOMEONE PLEASE HELP ME ASAP PLEASE!!!​
lesya692 [45]

Hey there! :)

Answer:

-1/2.

Step-by-step explanation:

For a line to be perpendicular, the slope must be the negative reciprocal of the original. In this instance:

A line perpendicular to y = 2x + 7 must contain a slope that is the negative reciprocal of 2.

The negative reciprocal of 2 is -1/2. This is the slope of a perpendicular line.

5 0
4 years ago
Read 2 more answers
Solve the following equation algebraically show your work<br> 17 = -13 - 8x
cricket20 [7]

Answer

-3.75

Step-by-step explanation:

17=-13-8x (collect like terms )

17+13=-8x

30=-8x (divide both sides by -8)

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4 0
4 years ago
-3 + 4b + 6 = 9+ 4b - 6<br> O infinitely many solutions<br> O one solution<br> Ob=3<br> no solution
topjm [15]

Answer:

Infinitely many solutions

Step-by-step explanation:

-3 +4b+6=9+4b-6

subtract 4b on both sides( canceling equal terms on both sides)

calculate the sum:

-3+6=9-6

-3+6= 3

9-6=3

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8 0
3 years ago
Find [5(cos 330 degrees + I sin 330 degrees)]^3
earnstyle [38]
Given a complex number in the form:
z= \rho [\cos \theta + i \sin \theta]
The nth-power of this number, z^n, can be calculated as follows:

- the modulus of z^n is equal to the nth-power of the modulus of z, while the angle of z^n is equal to n multiplied the angle of z, so:
z^n = \rho^n [\cos n\theta + i \sin n\theta ]
In our case, n=3, so z^3 is equal to
z^3 = \rho^3 [\cos 3 \theta + i \sin 3 \theta ] = (5^3) [\cos (3 \cdot 330^{\circ}) + i \sin (3 \cdot 330^{\circ}) ] (1)
And since 
3 \cdot 330^{\circ} = 990^{\circ} = 2\pi +270^{\circ}
and both sine and cosine are periodic in 2 \pi,  (1) becomes
z^3 = 125 [\cos 270^{\circ} + i \sin 270^{\circ} ]

6 0
4 years ago
Trong mặt phẳng tọa độ cho tam giác ABC biết các đỉnh A(-1,2), B(4,7) và trọng tâm tam giác G(3,2). Viết phương trinh đường thẳn
ExtremeBDS [4]
Can you translate so i can help you out .
8 0
3 years ago
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