Hey there! :)
Answer:
-1/2.
Step-by-step explanation:
For a line to be perpendicular, the slope must be the negative reciprocal of the original. In this instance:
A line perpendicular to y = 2x + 7 must contain a slope that is the negative reciprocal of 2.
The negative reciprocal of 2 is -1/2. This is the slope of a perpendicular line.
Answer
-3.75
Step-by-step explanation:
17=-13-8x (collect like terms )
17+13=-8x
30=-8x (divide both sides by -8)
30/-8=-8x/-8
-3.75=x
Answer:
Infinitely many solutions
Step-by-step explanation:
-3 +4b+6=9+4b-6
subtract 4b on both sides( canceling equal terms on both sides)
calculate the sum:
-3+6=9-6
-3+6= 3
9-6=3
3=3
Given a complex number in the form:
![z= \rho [\cos \theta + i \sin \theta]](https://tex.z-dn.net/?f=z%3D%20%5Crho%20%5B%5Ccos%20%5Ctheta%20%2B%20i%20%5Csin%20%5Ctheta%5D)
The nth-power of this number,

, can be calculated as follows:
- the modulus of

is equal to the nth-power of the modulus of z, while the angle of

is equal to n multiplied the angle of z, so:
![z^n = \rho^n [\cos n\theta + i \sin n\theta ]](https://tex.z-dn.net/?f=z%5En%20%3D%20%5Crho%5En%20%5B%5Ccos%20n%5Ctheta%20%2B%20i%20%5Csin%20n%5Ctheta%20%5D)
In our case, n=3, so

is equal to
![z^3 = \rho^3 [\cos 3 \theta + i \sin 3 \theta ] = (5^3) [\cos (3 \cdot 330^{\circ}) + i \sin (3 \cdot 330^{\circ}) ]](https://tex.z-dn.net/?f=z%5E3%20%3D%20%5Crho%5E3%20%5B%5Ccos%203%20%5Ctheta%20%2B%20i%20%5Csin%203%20%5Ctheta%20%5D%20%3D%20%285%5E3%29%20%5B%5Ccos%20%283%20%5Ccdot%20330%5E%7B%5Ccirc%7D%29%20%2B%20i%20%5Csin%20%283%20%5Ccdot%20330%5E%7B%5Ccirc%7D%29%20%5D)
(1)
And since

and both sine and cosine are periodic in

, (1) becomes