Basically this means it’s mirroring across the y axis on the opposite side
Calculate R8 for f (x) =10−x
over [3,5]. Here is the solution:
R8 = ∫ [3..5] (10 - x) dx
= [ (50 - 25/2 ) - ( 30 - 9/2 ) ]
= ( 75/2 – 51/2 ) = 24/2
<span>= 12</span>
Answer/Step-by-step explanation:
1. B = 180 - (90 + 58) (sum of triangles)
B = 32°
Let's find a and b using trigonometric ratios:
Reference angle = 58°
Opposite = a = ?
Hypotenuse = c = 27
Adjacent = b = ?
✔️To find a, apply SOH:
Sin 58 = Opp/Hyp
Sin 58 = a/27
a = 27*Sin 58
a = 22.8972986 ≈ 22.9 (nearest tenth)
✔️To find b, apply CAH:
Cos 58 = Adj/Hyp
Cos 58 = b/27
b = 27*Cos58
b = 14.3 (nearest tenth)
2. B = 180 - (90 + 63) (sum of triangles)
B = 27°
Let's find a and b using trigonometric ratios:
Reference angle = 63°
Opposite = a = 11
Hypotenuse = c = ?
Adjacent = b = ?
✔️To find b, apply TOA:
Tan 63 = Opp/Adj
Tan 63 = 11/b
b = 11/Tan 63
b = 5.6 (nearest tenth)
✔️To find c, apply SOH:
Sin 63 = Opp/Hyp
Sin 63 = 11/c
c = 11/Sin 63
c = 12.3 (nearest tenth)
Answer:
- use the HL postulate
- corresponding angles are congruent; corresponding sides are congruent
Step-by-step explanation:
See below for the marking.
a) Marking the right triangles per the given information, we see that the hypotenuses and one leg are congruent. We can use the HL postulate of congruence to conclude the triangles are congruent.
__
b) ∆CPS ≅ ∆WPD, so the following parts are congruent:
- ∠C ≅ ∠W
- ∠P (in ∆CPS) ≅ ∠P (in ∆WPD) — these are vertical angles
- ∠S ≅ ∠D
- CP ≅ WP
- PS ≅ PD
- CS ≅ WD
Answer:
I got 40210.1
Step-by-step explanation:
4,567.89+7,894.56=12462.45
12462.45+1,232.45=13694.9
13694.9+1,474.10=15169
15169+2,585.20=17754.2
17754.2+3696.36=21450.56
21450.56+3,214.56=24665.12
24665.12+6,545.65=31210.77
31210.77+7,898.78=39109.55
39109.55+1.100.55=40210.1