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mrs_skeptik [129]
3 years ago
6

Your teacher is giving you a test worth 150 points. Some questions are worth 3 points and the rest are worth 5 points. There are

46 questions on the test. How many of each type of question are on the test
Mathematics
1 answer:
trasher [3.6K]3 years ago
7 0
Set up a system of equations with x being 5 point questions, and y being 3 point questions

x+y=46

5x+3y=105

from here you can set y= 46-x

5x+ 3(46-x)= 150

2x+138= 150

x=6, meaning there are 6 5 point questions

that means there has to be 40 3 point questions


Answer: 40 3 point questions and 6 5 point questions

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4^3 is equivalent to? *
GREYUIT [131]

Answer:

4+4+4

Step-by-step explanation:

4^3 means 4 cubed which is equal to 4 added three time

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3 years ago
5x + 5 equals 16 - 6x​
bulgar [2K]

Answer:x=1

Step-by-step explanation:

5 0
3 years ago
Let the following sample of 8 observations be drawn from a normal population with unknown mean and standard deviation:
Vikentia [17]

Answer:

a

   \= x  = 18.5  ,  \sigma =  5.15

b

 15.505 < \mu <  21.495

c

 14.93 < \mu <  22.069

Step-by-step explanation:

From the question we are are told that

    The  sample data is  21, 14, 13, 24, 17, 22, 25, 12

     The sample size is  n  = 8

Generally the ample mean is evaluated as

        \= x  =  \frac{\sum x  }{n}

        \= x  =  \frac{  21 + 14 + 13 + 24 + 17 + 22+ 25 + 12  }{8}

         \= x  = 18.5

Generally the standard deviation is mathematically evaluated as

         \sigma =  \sqrt{\frac{\sum (x- \=x )^2}{n}}

\sigma =  \sqrt{\frac{\sum ((21 - 18.5)^2 + (14-18.5)^2+ (13-18.5)^2+ (24-18.5)^2+ (17-18.5)^2+ (22-18.5)^2+ (25-18.5)^2+ (12 -18.5)^2 )}{8}}

\sigma =  5.15

considering part b

Given that the confidence level is  90% then the significance level is evaluated as

         \alpha  =  100-90

         \alpha  = 10\%

         \alpha  = 0.10

Next we obtain the critical value of  \frac{ \alpha }{2}  from the normal distribution table the value is  

     Z_{\frac{ \alpha }{2} }  =  1.645

The margin of error is mathematically represented as

      E =  Z_{\frac{ \alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

=>    E =1.645  *  \frac{5.15 }{\sqrt{8} }

=>     E =  2.995

The 90% confidence interval is evaluated as

       \= x  -  E < \mu <  \= x +  E

substituting values

       18.5 -  2.995 < \mu <  18.5 +  2.995

       15.505 < \mu <  21.495

considering part c

Given that the confidence level is  95% then the significance level is evaluated as

         \alpha  =  100-95

         \alpha  = 5\%

         \alpha  = 0.05

Next we obtain the critical value of  \frac{ \alpha }{2}  from the normal distribution table the value is  

     Z_{\frac{ \alpha }{2} }  =  1.96

The margin of error is mathematically represented as

      E =  Z_{\frac{ \alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

=>    E =1.96  *  \frac{5.15 }{\sqrt{8} }

=>     E = 3.569

The 95% confidence interval is evaluated as

       \= x  -  E < \mu <  \= x +  E

substituting values

       18.5 - 3.569 < \mu <  18.5 +  3.569

       14.93 < \mu <  22.069

8 0
3 years ago
Need help this is my last chance
yuradex [85]
I don’t know the answer but Don’t try to open that link. I’ve seen a lot of people using it. Stay safe:)
3 0
3 years ago
Read 2 more answers
Find the Value of x so that the ratios are equivalent.
guajiro [1.7K]

x=45

9 x

12 60

x=9×60 divided by 12

9×60=540

540divided by 12=45

7 0
3 years ago
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