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Gekata [30.6K]
3 years ago
15

Find the value of x.

Mathematics
1 answer:
madreJ [45]3 years ago
3 0

Answer:

40

Step-by-step explanation

x=40 because if you time these in like this:

3(40)-10= 110

40+15=55

If you user 65 it'll be wrong because:

3(65)-10=185    

And the whole thing is only 180 :]

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Its

C. Draw a line connecting the the intersection of the arcs below and above the segment.

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What is the opposite operation of squaring? Using this opposite operation, rewrite the equation from question 1 so s is by itsel
Radda [10]
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5 0
2 years ago
An image of a parabolic lens is projected onto a graph. The y-intercept of the graph is (0, 90), and the zeros are 5 and 9. Whic
seraphim [82]
Given:

y-intercept of the graph: (0, 90)
zeros: 5 and 9

The equation that models the function based on the zeros given, is either

y = 90 (x-5) (x-9)
or
y= 2(x-5)(x-9)

try solving for the y-intercept of each function, 

y = 90 (0-5) (0-9)
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(0, 4050)

y = 2(0-5) (0-9)
y = 90
(0, 90)

therefore, the equation that models the function is y = 2(x-5)(x-9)

8 0
3 years ago
Read 2 more answers
Simplify 7(exponent 6) multiplied by 7 (exponent 5)
Lady_Fox [76]
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Thank you!
7 0
3 years ago
F(x)=x-1/x^2-x-6 which is the graph of
hoa [83]

Answer:

The graph is attached below.

Step-by-step explanation:

<em>As you have not added the graph, so I will be solving the function for a graph.</em>

Given the function

f\left(x\right)=x-\frac{1}{x^2}-x-6

x-\mathrm{axis\:interception\:points\:of\:}-\frac{1}{x^2}-6:

\mathrm{x-intercept\:is\:a\:point\:on\:the\:graph\:where\:}y=0

-\frac{1}{x^2}-6=0

-1-6x^2=0

\mathrm{No\:Solution\:for}\:x\in \mathbb{R}

\mathrm{No\:x-axis\:interception\:points}

y-\mathrm{axis\:interception\:point\:of\:}-\frac{1}{x^2}-6:

y\mathrm{-intercept\:is\:the\:point\:on\:the\:graph\:where\:}x=0

As we know that the domain of a function is the set of input or argument values for which the function is real and defined.

\mathrm{Domain\:of\:}\:-\frac{1}{x^2}-6\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x0\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:0\right)\cup \left(0,\:\infty \:\right)\end{bmatrix}

\mathrm{Since}\:x=0\:\mathrm{is\:not\:in\:domain}

\mathrm{No\:y-axis\:interception\:point}

\mathrm{Asymptotes\:of}\:-\frac{1}{x^2}-6:\quad \mathrm{Vertical}:\:x=0,\:\mathrm{Horizontal}:\:y=-6

\mathrm{Range\:of\:}-\frac{1}{x^2}-6:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)

The graph is attached below.

5 0
3 years ago
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