Plzzzzzzzzzzzs help me
1 answer:
You might be interested in
Step-by-step explanation:
Let's pick two points on the line: and
Let's calculate the slope of this line using these points:
With this value of the slope, we can write the general slope-intercept form of the equation as
To solve for the y-intercept b, let's use either P1 or P2. I'm going to use P2:
Therefore, the slope-intercept form of the equation is
Consider the function 
, which has derivative 
.
The linear approximation of
for some value 
within a neighborhood of 
is given by
Let
. Then 
can be estimated to be
![\sqrt[3]{63.97}\approx4-\dfrac{0.03}{48}=3.999375](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B63.97%7D%5Capprox4-%5Cdfrac%7B0.03%7D%7B48%7D%3D3.999375)
Since
for 
, it follows that must be strictly increasing over that part of its domain, which means the linear approximation lies strictly above the function . This means the estimated value is an overestimation.
Indeed, the actual value is closer to the number 3.999374902...
The linear approximation of
Let
Since
Indeed, the actual value is closer to the number 3.999374902...