Suppose EG=3, EB=8, A(F)=7, m∠EBG=23, m∠EGF=32, and m∠CAE=51. Find m∠CAF.
1 answer:
Answer:
m∠CAF is 28°
Step-by-step explanation:
The given parameters are;
EG = 3, EB = 8, A_F = 7, m∠EBG = 23°, ∠EGF 32°, and m∠CAE = 51°
From the diagram, we have;
m∠EBG = m∠EAD ; Given
Therefore, m∠EAD = 23°
m∠CAE = m∠CAF + m∠EAD Angle addition postulate
Therefore, we have;
51° = m∠CAF + 23°
m∠CAF = 51° - 23°
m∠CAF = 28°
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