Question

Solve the system of equations below x-2y=3 2y-3y=9

Answer 1

First you solve 2y-3y=9.
$2y - 3y = 9 \\ subtract \: 2y \: and \: 3y \\ - y = 9 \\ divide \: by \: - 1 \\ y = - 9$
Now that you have y, then you substitute y into x-2y=3 to find X

$x - 2( - 9) = 3 \\ multiply \: - 9 \times - 2 \\ x + 18 = 3 \\ subtract \: 18 \: on \: both \: sides \\ x = - 15$
Your solution is (-15, -9)