The answer to this probability question is .86 or 86%. The probability that a batch of 10,000 batteries will contain at least 175 defective batteries is 86 percent. I calculated the failure rate of 10,000 batteries (10k*.015) and yielded 150, meaning there will be 150 batteries that will be defective in a set of 10,000. Then i divided 150 by 175 to get the probability.
Juan's time = x
Yumi's time = x + 2
Yumi's distance = 3 miles
Juan's distance = 2 miles
Rate = distance/time
Juan's rate = 2/x
Yumi's rate = 3/(x + 2)
The rates are equal so:
2/x = 3/(x + 2)
2x + 4 = 3x
x = 4 hours
Yumi's time = 4 + 2 = 6 hours
The answer is D.
Answer:
28
Step-by-step explanation:
Answer:
146.41
Step-by-step explanation:
third order determinant = determinant of 3×3 matrix A
given ∣A∣=11
det (cofactor matrix of A) =set (transpare of cofactor amtrix of A) (transpare does not change the det)
=det(adjacent of A)
{det (cofactor matrix of A)} ^2 = {det (adjacent of A)}
^2
(Using for an n×n det (cofactor matrix of A)=det (A)^n−1
)
we get
det (cofactor matrix of A)^2 = {det(A) ^3−1
}^2
=(11)^2×2 = 11^4
=146.41
Answer:
Given:
Mean, u = 2100
A golf magazine reports the mean gain to be $2100, while the teaching professional believes the average gain is not $2100.
Here the null and alternative hypotheses would be:
Null hypothesis:
H0: u = 2100
Alternative hypothesis:
Ha: u ≠ 2100
b) Here, given the level of significance,
as 0.10. This means that:
The probability that the null hypothesis H0 is rejected when average gain is $2100 is 0.10
