Answer:
Keep logs of applications activities in your system.
Explanation:
<em>Event viewer contains applications activities logs such as errors encountered by the application, prompts, and warnings in the system. This could be handy in terms of troubleshooting as system admins or users can take a look at the logs and examine the problems.</em>
<em>You can open or run event viewer in Windows by simply type "event viewer" in the start menu and click on the result or icon.</em>
Answer:
The correct matching are as follows--
- (WAN) match from the B option,
- (LAN) match from the C option,
- (MAN) match from the A option,
- (PAN) match from the E option,
- (HAN) match from the D option,
Explanation:
- WAN(Wide area network). It is a network that connects all over the world to share information and data. This concept fits on option B. Hence it is a correct choice for WAN.
- LAN(Local area network), it is a network which is used in some small area or organization to share the information within the organization. This concept fits on option C. Hence it is a correct choice for LAN.
- MAN(Metropolitan area network), it is a network which connects two or more office in a city then it comes in the categories of MAN network. This concept fits on the option A. Hence it is a correct choice for MAN.
- PAN(Personal area network). It is a network that connects the network to share information for personal use. This concept fits on option E. Hence it is a correct choice for PAN.
- HAN(Home area network). It is a network that connects networks for a home connection. This concept fits on option D. Hence it is a correct choice for HAN.
Answer:
Broken Firewall, Piracy, Malware, Virus, adware
Explanation:
Please give brainliest if this helps
Answer:
#include <iostream>
#include <cstdlib>
#include <ctime>
using namespace std;
int main(){
int n;
cout<< "Enter the row and column length: ";
cin>> n;
int array_one[n][n];
int array_transpose[n][n];
for (int i = 0; i < n; i++){
for (int j= 0; j < n; j++){
srand((unsigned) time(0));
array_one[i][j] = (rand() % 4000)
array_transpose[j][i] = array_one[i][j];
}
}
}
Explanation:
The C source code has three variables, 'array_one', array_transpose' (both of which are square 2-dimensional arrays), and 'n' which is the row and column length.
The program loops n time for each nth number of the n size to assign value to the two-dimensional array_one. the assign values to the array_transpose, reverse the 'i' and 'j' values to the two for statements for array_one to 'j' and 'i'.
its answer in binary is 1000 and in decimal is 8.