Answer:
15 inches
Step-by-step explanation:
We assume that the edge of the small square is x (inches).
As the edge of the larger square is 2 inches greater than that of the smaller one, so that the edge of the larger square = edge of the small square + 2 = x + 2 (inches)
The equation to calculate the are of a square is: <em>Area = Edge^2 </em>
So that:
+) The area of the larger square is: <em>Area large square = </em>
<em> (square inches)</em>
+) The area of the smaller square is: <em>Area small square = </em>
<em>(square inches)</em>
<em />
As difference in area of both squares are 64 square inches, so that we have:
<em>Area large square - Area small square = 64 (square inches)</em>
<em>=> </em>
<em />
<em>=> </em>
<em />
<em>=> 4x + 4 = 64</em>
<em>=> 4x = 64 - 4 = 60 </em>
<em>=> x = 60/4 = 15 (inches)</em>
So the length of an edge of the smaller square is 15 inches
Answer:
C Infinitely Many Solutions
Step-by-step explanation:
i put the 2 equations into Desmos Graphing Calculator and they are the same line so it has infinitely many solutions.
The general form of the equation we need to find is (x - h)^2 = 4p(y- k).
The center is the distance between the directrix and focus.
So, center (h, k) = (3, 3/2) .
P = distance from center to the focus and it just so happens to be 1.5.
We now plug everything into the formula given above.
(x - 3)^2 = 4(1.5)(y - 3/2)
(x - 3)^2 = 6(y - 3/2)
Done!
I'd say yes. If you use the diagonal as a reference. Take the square and set your compass to the width of the diameter of the square. Now put it on the page and mark a point. Put the point of the compass on that mark and make another mark. Now you can connect the two marks with the straight edge and you have a line that, if you made a square with sides that long, it'd have 2x the area of the first one. That's because the diagonal is the square root of 2 larger than one side. Square the square root of 2 and you've got 2. You lust need to make a perpendicular line to the first one to get the box going.
Question 1
angle 1=angle 3
angle 3=37
therefore angle 1=37
