Answer:
The answer is 10m + 7n - 14
Step-by-step explanation:
Q = 7m + 3n
R = 11 - 2m
S = n + 5
T = -m - 3n + 8
[Q - R] + [S - T] is
[ 7m + 3n - (11 - 2m) ] + [ n + 5 - ( - m - 3n+8)]
Solve the terms in the bracket first
That's
( 7m + 3n - 11 + 2m ) + ( n + 5 + m + 3n - 8)
( 9m + 3n - 11 ) + ( m + 4n - 3)
<u>Remove the brackets</u>
That's
9m + 3n - 11 + m + 4n - 3
<u>Group like terms</u>
9m + m + 3n + 4n - 11 - 3
The final answer is
<h3>
10m + 7n - 14</h3>
Hope this helps you
CB = DA = √3*3+1*1 = √10
CD = BA = √2*2+1*1 = √5
Sum is 2√10 + 2√5 ≈ 10.8. So answer A.
Answer:
Step-by-step explanation:
The trigonometric identity is :
We need to express secθ in terms of tanθ.
The above equation becomes,
Hence, this is the required solution.
