Mr. Reynolds used 2 pounds of
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Answer:
On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 1, and the horizontal asymptote is at y = 4
Step-by-step explanation:
The given function is presented as follows;
From the given function, we have;
When x = 1, the denominator of the fraction, , which is (x - 1) = 0, and the function becomes,
therefore, the function in undefined at x = 1, and the line x = 1 is a vertical asymptote
Also we have that in the given function, as <em>x</em> increases, the fraction tends to 0, therefore as x increases, we have;
Therefore, as x increases, f(x) → 4, and 4 is a horizontal asymptote of the function, forming a curve that opens up and to the right in quadrant 1
When -∞ < x < 1, we also have that as <em>x</em> becomes more negative, f(x) → 4. When x = 0, . When <em>x</em> approaches 1 from the left, f(x) tends to -∞, forming a curve that opens down and to the left
Therefore, the correct option is on a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 1, and the horizontal asymptote is at y = 4.
Non-negative integers are positive integers or zero.
1. When then there are such possible cases for
and
In total 11 solutions for
2. For there are such possible cases for
and
In total 10 solutions for
3. This process gives you
- for
- 9 solutions;
- for
- 8 solutions;
- for
- 7 solutions;
- for
- 6 solutions;
- for
- 5 solutions;
- for
- 4 solutions;
- for
- 3 solutions;
- for
- 2 solutions;
- for
- 1 solution.
4. Add all numbers of solutions:
Answer: there are 66 possible solutions (with non-negative integer variables)