Question

Please help me with this, Thank you

Answer 1

Answer:

y = $\frac{6}{5}$

Step-by-step explanation:

Given

6 | 5y - 1 | - 1 = 29 ( add 1 to both sides )

6 | 5y - 1 | = 30 ( divide both sides by 6 )

| 5y - 1 | = 5

The absolute value function always returns a positive value. However, the expression inside can be positive or negative, thus

5y - 1 = 5 ( add 1 to both sides )

5y = 6 ( divide both sides by 5 )

y = $\frac{6}{5}$

OR

- (5y - 1) = 5, that is

- 5y + 5 = 5 ( subtract 5 from both sides )

5y = 0 ⇒ y = 0

As a check substitute these values into the left side and if equal to the right side then they are the solutions.

x = 0 : 6|0 - 1 | - 1 = 6 | - 1| - 1 = 6(1) - 1 = 6 - 1 = 5 ≠ 29

x = $\frac{6}{5}$ : 6 | 6 - 1 | - 1 = 6(5) - 1 = 30 - 1 = 29

Thus x = $\frac{6}{5}$ is a solution, x = 0 is extraneous