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AnnyKZ [126]
3 years ago
14

Pls help:) i feel so guilty for asking questions

Mathematics
1 answer:
expeople1 [14]3 years ago
3 0

Answer:

Step-by-step explanation:

AB:

d = sqrt ( (−5−2)^2 + (−2−(−8))^2)

d = sqrt( (−7)^2 + (6)^2  )

d = sqrt(49+36)

d = sqrt(85)

d = 9.219544

BC:

d = sqrt ( (−7−(-5))^2+(3−(−2))^2 )

d = sqrt( (−2)^2 + (5)^2  )

d = sqrt(4+25)

d = sqrt(29)

d = 5.385165

AC:

d = sqrt ( (−7−(2))^2+(3−(−8))^2 )

d = sqrt( (−9)^2 + (11)^2  )

d = sqrt(81+121)

d = sqrt(202)

d = 14.21267

DE:

d = sqrt ( (−11−(-9))^2+(12−7)^2 )

d = sqrt( (−2)^2 + (5)^2  )

d = sqrt(4+25)

d = sqrt(29)

d = 5.385165

EF:

d = sqrt ( (−2−(-11))^2+(1−12)^2 )

d = sqrt( (9)^2 + (-11)^2  )

d = sqrt(81+121)

d = sqrt(202)

d =14.21267

DF:

d = sqrt ( (−2−(-9))^2+(1−7)^2 )

d = sqrt( (7)^2 + (-6)^2  )

d = sqrt(49+36)

d = sqrt(85)

d = 9.219544

Yes, the triangles are congruent because the lengths are the same.

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Please help! i cant solve it​
3241004551 [841]

a ≈ 5.2, B ≈ 50°, C ≈ 95°

Solution:

Given data:

A = 35°, b = 7, c = 9

Using cosine law,

a^{2}=b^{2}+c^{2}-2 b c \cos A

a^{2}=7^{2}+9^{2}-2 (7)(9) \cos 35^\circ

a^{2}=49+81-126 (0.82)

a^{2}=26.68

Taking square root on both sides.

a ≈ 5.2

Using sine law,

$\frac{\sin A}{a} =\frac{\sin B}{b}

$\frac{\sin 35^\circ}{5.2} =\frac{\sin B}{7}

Multiply by 7 on both sides.

$\frac{0.5735}{5.2}\times 7 =\sin B

Switch the sides.

Sin B = 0.772

B=\sin^{-1}0.772

B ≈ 50°

Sum of all the angles of a triangle = 180°

A + B + C = 180°

35° + 50° + C = 180°

85° + C = 180°

C = 180° - 85°

C = 95°

Hence a ≈ 5.2, B ≈ 50°, C ≈ 95°.

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