3 years ago

Solve the following system of equations using substitution.

1 answer:

stira [4]3 years ago

4 0

It is A maybe use your calculator

You might be interested in

ch4aika [34]

Step-by-step explanation:

Question 46.

$(2\sqrt{5}-\sqrt{2} )^2=(2\sqrt{5})^2-2*2\sqrt{5}*\sqrt{2} +(\sqrt{2})^2 } =4*5-4*\sqrt{2*5} +2=\\=20-4\sqrt{10}+2=22-4\sqrt{10}.$

Answer: E. None of these.

Question 47.

$\frac{4\sqrt{5} }{\sqrt{3} } =\frac{4*\sqrt{5}*\sqrt{3} }{\sqrt{3} *\sqrt{3} } =\frac{4*\sqrt{5*3} }{3}=\frac{4\sqrt{15} }{3} .$

Answer: E. None of these.

6 0

2 years ago

elixir [45]

Answer:

width = 5k^2

length( 3k^2 +7k +4)

Step-by-step explanation:

15k^4 +35k^3 +20k^2

The width is the greatest common factor

We can factor 5k^2 out

5k^2( 3k^2 +7k +4)

The length is what is inside the parentheses

4 0

4 years ago

Sphinxa [80]

Expanding the right side:-

5x - 4 = 5x - 15 + 11
5x - 4 = 5x - 4

left side = right side so there are infinitely many solutions

7 0

3 years ago

anyanavicka [17]

the area is about 62 in.2

Hope this helps;-)

7 0

3 years ago

creativ13 [48]

A box of chalk cost 4$ and the staples cost 3$ a piece.

5 0

3 years ago