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almond37 [142]
3 years ago
9

PLS help asap bt 1230 pt help thank you will brainliest

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
6 0

Answer:

85

Step-by-step explanation:

So you train of though might lead you to soemthing like this: it must be 90 degrees, since that looks like a 90 degree triangle, and there are 180 degrees in a line. So 90 degrees and 90 degrees make up the 180.

That is exactly what I though.

But, its a bit different from that. We do not know for sure that its a 90 degree traingle. Depending on the angle of the traingle, the outcome of the mystery number is different.

So, to find the angle of the trainge, lets take our 155 degree line.

Now, this is just a simple line. We know the line is 180, and that the other number must add onto 155 to make 180:

180-155=missing angle

=

25. So we know that the smallest angle of the traingle is 25.

We also know that a traingle has a total of 180 degrees.

We can add the 60 degrees and our new 25 degrees, subtract if from 180, and we will get our last angle of the traingle we need to solve:

60+25

=

85

Now subtract it from 180:

180-85

=

95

So that last angle of the traingle is 95.

Now, we need to solve the missing angle of the line that will give us the answer.

Again, we know the line has to be 180, so lets subtract 95 from that:

180-95

=

85

So we know that the missing angle answer is 85!

I hope this isnt too confusing and helps! :)

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Romashka-Z-Leto [24]
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6 0
3 years ago
Form a polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3
polet [3.4K]

The polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3 is x^3-3x^2-x+3=0

Step-by-step explanation:

We need to find a polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3.

If -1, 1 and 3 are real zeros, it can be written as:

x= -1, x= 1, and x = 3

or x+1=0, x-1=0 and x-3=0

Finding polynomial by multiply these factors:

(x+1)(x-1)(x-3)=0\\(x+1)(x(x-3)-1(x-3))=0\\(x+1)(x^2-3x-x+3)=0\\(x+1)(x^2-4x+3)=0\\x(x^2-4x+3)+1(x^2-4x+3)=0\\x^3-4x^2+3x+x^2-4x+3=0\\Combining\,\,like\,\,terms:\\x^3-4x^2+x^2+3x-4x+3=0\\x^3-3x^2-x+3=0

So, The polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3 is x^3-3x^2-x+3=0

Keywords: Real zeros of Polynomials

Learn more about Real zeros of Polynomials at:

  • brainly.com/question/1464739
  • brainly.com/question/2568692
  • brainly.com/question/10771256

#learnwithBrainly

8 0
3 years ago
The perimeter of an equilateral triangle is 3 (+ 5). The perimeter of a rectangle is 2 (2x - 3) + 2(2). If the perimeters of the
TiliK225 [7]

Answer:

3.25

Step-by-step explanation:

Perimeter of triangle = 3(5) = 15 cm

Perimeter of rectangle = 2(2x - 3 + 4)

Perimeter = 2(2x + 1)

Perimeter = 4x + 2

4x + 2 = 15

4x = 15 - 2

4x = 13

x = 13/4

x = 3.25

5 0
3 years ago
Es 56 un primer o un número compuesto
Angelina_Jolie [31]
Es compuesto
dame una gracias sin esto te ayudo!
8 0
3 years ago
Read 2 more answers
Please please help me
Valentin [98]

Answer:

a) Acute

Step-by-step explanation:

   To clasify the triangle as Acute, Right, or Obtuse, we use the converse of the pythagorean theorem and see if c^2 is greater, less than, or equal to b^2+a^2.

So 16^2 ? 11^2 + 12^2

Since 11^2 +12^2 = 265 and 16^2 is 256, c^2 is less than b^2+a^2. So the triangle is acute.

7 0
3 years ago
Read 2 more answers
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