What are 3 different ways to make the number 15,638 with only hundreds,tens,ones?

PLEASE PLEASE PLEASE HELP

Airida [17]

Answer:

64 cm

Step-by-step explanation:

u just add each of the langht of the squar

3 0

4 years ago

Find out for what value of the variable:

Burka [1]

Answer:

$a=-1,\ a=-5$

$x=-2+i,\ -2-i$

Step-by-step explanation:

<u>Equations</u>

We have two cases where some variable is required to be found such that some condition is met. The first case is about finding the value of a that complies:

$a^2+7a+6=a+1$

Rearranging

$a^2+6a+5=0$

Factoring:

$(a+1)(a+5)=0$

There are two solutions:

$a=-1,\ a=-5$

The second case requires us to find the value of x such that

$3x^2-x+1 =2x^2+5x-4$

Rearranging

$x^2+4x+5=0$

This second-degree equation has no real roots. We'll offer the imaginary (complex) solutions:

$x=-2+i,\ -2-i$

5 0

3 years ago

Imagine you have some workers and some handheld computers that you can use to take inventory at a warehouse. There are diminishi

Svet_ta [14]

Answer:

a. $1.03

b. $0.93

c. 0.98

d. 2 workers

Step-by-step explanation:

a. Given that:

1 computer : 1 worker : inventory 150 items per hour
1 computer : 2 workers : inventory 200 items per hour
1 computer : 3 workers : inventory 220 items per hour
1 computer : 4+ workers : fewer than 235 items per hour
Cost: $100 per computer ; $25 per worker

The fixed production factor in the warehouse is the computer used:

-One computer used, but the number of users is varied to inventory a specified number of items.

-The variable production factor is the number of workers assigned per one computer.

#The cost of inventorying a single item by one worker is:

$Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_1=\frac{125+30}{150}\\\\\\=1.03$

Hence, the cost of inventorying a single item is $1.03

b. Using the information provided above, the cost of inventorying a single item when two workers are assigned is :

$Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_2=\frac{125+2\times30}{200}\\\\\\=0.925$

Hence, the cost of inventorying a single item is $0.93

c.Using the information provided above, the cost of inventorying a single item when three workers are assigned is :

$Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_3=\frac{125+3\times30}{220}\\\\\\=0.98$

Hence, the cost of inventorying a single item is $0.98

d. To determine the most cost-effective job assignment, we calculate the cost of 4+ workers.

Take any number less than 235(say 234) as the inventory units:

$Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_4=\frac{125+4\times30}{234}\\\\\\=1.05$

From our calculations, it's clear that two workers per computer costs the least amount($0.93) per unit item. Hence, it is best to assign two workers per computer.

4 0

4 years ago

8.6 - 5.36 plz help me

olga nikolaevna [1]

Answer:

3.24

Step-by-step explanation:

It's really hard to explain things like this aha-

6 0

3 years ago

Read 2 more answers

ILL GIVE YOU BRAINLIST !! * have to get it right !!! * Find the slope of the line.