Answer:
Step-by-step explanation:
Let consider the following model:
The average is given by the following formula:
The maximum value is:
Amplitude is:
The sine function has a periodicity of , where is minimum is reached at
, when t = 30. The period of the cycle is:
The complete expression is:
The times associated with are, respectively:
Instants are, respectively:
Period is:
Answer:
It is not normally distributed as it has it main concentration in only one side.
Step-by-step explanation:
So, we are given that the class width is equal to 0.2. Thus we will have that the first class is 0.00 - 0.20, second class is 0.20 - 0.40 and so on(that is 0.2 difference).
So, let us begin the groupings into their different classes, shall we?
Data given:
0.31 0.31 0 0 0 0.19 0.19 0 0.150.15 0 0.01 0.01 0.19 0.19 0.53 0.53 0 0.
(1). 0.00 - 0.20: there are 15 values that falls into this category. That is 0 0 0 0.19 0.19 0 0.15 0.15 0 0.01 0.01 0.19 0.19 0 0.
(2). 0.20 - 0.40: there are 2 values that falls into this category. That is 0.31 0.31
(3). 0.4 - 0.6 : there are 2 values that falls into this category.
(4). 0.6 - 0.8: there 0 values that falls into this category. That is 0.53 0.53.
Class interval frequency.
0.00 - 0.20. 15.
0.20 - 0.40. 2.
0.4 - 0.6. 2.
Answer:
Least to Greatest:
Step-by-step explanation:
☆I converted all to decimal form so that it was easier to see which is greater.
▪0.95, 0.9, 0.951, 0.85, 0.94
☆Now I ordered them from least to greatest.
0.85, 0.9, 0.94, 0.95, 0.951
☆Then I simply switched them to the original form.