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WARRIOR [948]
3 years ago
10

he data represents the daily rainfall​ (in inches) for one month. Construct a frequency distribution beginning with a lower clas

s limit of 0.000.00 and use a class width of 0.200.20. Does the frequency distribution appear to be roughly a normal​ distribution? 0.310.31 0 0 0 0.190.19 0 0.150.15 0 0.010.01 0.190.19 0.530.53 0 0

Mathematics
1 answer:
Licemer1 [7]3 years ago
4 0

Answer:

It is not normally distributed as it has it main concentration in only one side.

Step-by-step explanation:

So, we are given that the class width is equal to 0.2. Thus we will have that the first class is 0.00 - 0.20, second class is 0.20 - 0.40 and so on(that is 0.2 difference).

So, let us begin the groupings into their different classes, shall we?

Data given:

0.31 0.31 0 0 0 0.19 0.19 0 0.150.15 0 0.01 0.01 0.19 0.19 0.53 0.53 0 0.

(1). 0.00 - 0.20: there are 15 values that falls into this category. That is 0 0 0 0.19 0.19 0 0.15 0.15 0 0.01 0.01 0.19 0.19 0 0.

(2). 0.20 - 0.40: there are 2 values that falls into this category. That is 0.31 0.31

(3). 0.4 - 0.6 : there are 2 values that falls into this category.

(4). 0.6 - 0.8: there 0 values that falls into this category. That is 0.53 0.53.

Class interval            frequency.

0.00 - 0.20.                   15.

0.20 - 0.40.                    2.

0.4 - 0.6.                        2.

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Answer:

-1.9

Step-by-step explanation:

3 0
2 years ago
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Mary has $65,000 to invest in two accounts. The first account is a private savings offering 6% annual interest and the second ac
const2013 [10]

Answer:

first account with 6% interest ( x ) = $46000

second account with 4% interest ( y ) = $19000

Step-by-step explanation:

Principal = $65000

first interest rate = 6%

second interest rate = 4%

assuming ; X = money invested in first account ,  Y = money invested in second account

hence :

( 65000 - y ) * 6% + ( 65000 - x ) * 4% = 3520

3900 - 0.06 y  + 2600 - 0.04 x = 3520

0.04 x + 0.06 y = 3900 + 2600 - 3520

0.04 x + 0.06 y = 2980 ----- ( 1)

        x + y = 65000  ------- ( 2 )

solve equation 1 and 2 simultaneously by elimination method

0.04 x + 0.06 y = 2980 ------  ( 3 )

0.06 x + 0.06 y = 3900 ------- ( 4 )

subtract equation 3 form equation 4

0.02 x  = 920 ,   hence x = $46000

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6 0
3 years ago
Find the distance between points A (10,-1) and B (-2,5). Round to the nearest tenth
bija089 [108]

Answer:

<h2>The answer is 13.4 units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

d =  \sqrt{ ({x1 - x2})^{2}  +  ({y1 - y2})^{2} }  \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

A (10,-1) and B (-2,5)

The distance is

|AB|  =  \sqrt{ ({10 + 2})^{2} +  ({ - 1 - 5})^{2}  }  \\  =  \sqrt{ {12}^{2}  +  ({ - 6})^{2} }  \\  =  \sqrt{144 + 36}  \:  \:  \:  \:  \:  \:  \:   \\  =  \sqrt{180}  \\  = 6 \sqrt{5}  \:  \:  \\  =13.416407

We have the final answer as

<h3>13.4 units to the nearest tenth</h3>

Hope this helps you

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