An acute triangle has sides measuring 10 cm and 16 cm. The length of the third side is unknown.

Simplify 18-2[x + (x - 5)].<br> O8-4x<br> 28 - 4x<br> 28 - 2x

densk [106]

Answer:

28-4x

Step-by-step explanation:

Step 1: Open most inner bracket and simplify

=18-2(x+x-5)

=18-2(2x-5)

Step 2: Expand brackets by multiplying 2 in and simplify

=18-2(2x)-2(-5)

=18-4x+10

=28-4x

Therefore the answer is 28-4x

3 0

2 years ago

Find the area of this parallelogram?

Jet001 [13]

So, the area of a parallelogram is the base times the height or

$a = b \times h$

a being area

b being base

h being height

the height is 8 cm and the base is 15 cm

(remember: the heght should be perpendicular to the base)

so we plug in 8 for h and 15 for b to get

$a = 15 \times 8$

and 15 × 8 = (10 × 8) + (5 × 8) = 80 + 40 =120

So the answer is 120

3 0

3 years ago

Zara is shopping at a furniture store with a budget of $1,500

Burka [1]

The Estimated total cost was $1564. Zara do not have eough money to buy the sofa and coffee table.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

She wants to buy a sofa for $924 and a coffee table for $640, hence:

Estimated total cost = 924 + 640 = $1564

The Estimated total cost was $1564. Zara do not have eough money to buy the sofa and coffee table.

Find out more on equation at: brainly.com/question/1214333

3 0

2 years ago

There are 3 people pulling on an object, the first person pulls with a force of 226 newtons at a direction of 145 degrees the se

Alona [7]

Answer:

$R=883.74N$

Step-by-step explanation:

From the question we are told that:

Force 1 $F_1=226N$

Force 2 $F_2=331N$

Force 3 $F_3=377N$

Direction 1 $\theta_1=145 degrees \approx 35 \textdegree (2nd qudrant)$

Direction 2 $\theta_2=303 degrees \approx 57 \textdegree (3rd qudrant)$

Direction 3 $\theta_3=77 degrees$

Generally Resolving forces to X axis is mathematically given by

$\sum f_x=337cos77+331cos57+226sin35$

$\sum f_x=351.596N$

Generally Resolving forces to Y axis is mathematically given by

$\sum f_y=337sin77+331sin57+226cos35$

$\sum f_x=810.788N$

Generally the equation for Resultant force R is mathematically given by

$R=\sqrt{\sum f_x^2+\sum f_x^2}$

$R=\sqrt{351.596^2+810.788^2}$

$R=883.74N$

7 0

2 years ago

Step by step workout of ;<br> log x^3+log 5x=5 log 2-log 2/5

Charra [1.4K]

Answer:

x = 2

Step-by-step explanation:

$log \: {x}^{3} + log \: 5x = 5log \: 2 - log \: \frac{2}{5} \\ \\ \therefore \: log( {x}^{3} \times 5x) = log {2}^{5} - log \: \frac{2}{5} \\ \\ \therefore \: log( 5{x}^{4}) = log 32 - log \: \frac{2}{5} \\ \\ \therefore \: log( 5{x}^{4}) = log \bigg(32 \times \frac{5}{2} \bigg) \\ \\ \therefore \: log( 5{x}^{4}) = log \bigg(16 \times 5) \\ \\ \therefore \: 5{x}^{4}= 16 \times 5 \\ \\ \therefore \: {x}^{4}= {2}^{4} \\ \\ \huge \purple{ \boxed{\therefore \: {x} = 2}}$

4 0

3 years ago