Help me please. Not sure how to solve this. Can someone show me how to do it step by step. -2/5x-9<9/10

1 answer:

7 0

Leave the x alone first. -2/5x<9/10+9. then -2/5×<99/10. multiply both sides by 5 you'll get -99/2 < 2x. then divide both sides by 2 you'll get -99/4 < ×

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1. A 20 kg object is thrown with an initial upward velocity of 2 m/s. If air resists motion of the object by 4 N for each m/s, w

dlinn [17]

Answer:

49 m/s

Step-by-step explanation:

We don't know what your model is, so we'll solve this based on the balance of forces. Air resistance exerts an upward force of ...

(4 N/(m/s))v

Gravity exerts a downward force of ...

(20 kg)(9.8 m/s²) = 196 N

These are balanced (no net acceleration) when ...

(4 N/(m/s))v = 196 N

v = (196 N)/(4 N/(m/s)) = 49 m/s

The terminal velocity is expected to be 49 m/s.

4 0

3 years ago

PLEASE HELPPPP!!

geniusboy [140]

Answer:

qwsedfgh

Step-by-step explanation:

7 0

3 years ago

NEED MATH HELP QUICK!

Korolek [52]

Answer:

Minimum = 14

$Q_1=23$

Median = 32

$Q_3=49$

Maximum = 65

Step-by-step explanation:

Step 1: Put your numbers in ascending order (from smallest to largest). For this particular data set, the order is

14, 18, 28, 29, 32, 44, 48, 50, 65

Step 2: Find the minimum and maximum for your data set. Now that your numbers are in order, this should be easy to spot.

Minimum = 14

Maximum = 65

Step 3: Find the median. The median is the middle number. The middle number in your list is 32, so

Median = 32

Step 4: Place parentheses around the numbers above and below the median.

(14, 18, 28, 29), 32, (44, 48, 50, 65)

Step 5: Find Q1 and Q3. Q1 can be thought of as a median in the lower half of the data, and Q3 can be thought of as a median for the upper half of data.

First quartile

$\bf{Q_1=\dfrac{18+28}{2}=\dfrac{46}{2}=23}$