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romanna [79]
2 years ago
11

I need help with this will mark!!

Mathematics
1 answer:
adoni [48]2 years ago
4 0

Answer:

look it up

Step-by-step explanation:

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How to identify the independent and dependent variable?
strojnjashka [21]
Independent-a variable (often denoted by x) whose variation does not depend on that of another

dependant-a variable (often denoted by y) whose value depends on that of another.
8 0
3 years ago
Pls help being timed and I don’t understand
shepuryov [24]

Answer:

f ( -2 ) = 30

g ( -2 ) = 3

Step-by-step explanation:

when it says f(x) and then has f(-2) - you fill in all x's in the equation with -2.. like this:

f(x) = -7(-2-2) +2                         g(x) = 2(-2)^2 -5

f(x) = -7(-4) +2                             g(x) = 2(4) -5

f(x) = 28 + 2                                g(x) = 8 - 5

f(x) = 30                                      g(x) = 3

hope this helps!!

6 0
3 years ago
If r and s are positive integers, is \small \frac{r}{s} an integer? (1) Every factor of s is also a factor of r. (2) Every prime
Yuri [45]

Answer:

<em>If statement(1) holds true, it is correct that </em>\small \frac{r}{s}<em> is an integer.</em>

<em>If statement(2) holds true, it is not necessarily correct that </em>\small \frac{r}{s}<em> is an integer.</em>

<em></em>

Step-by-step explanation:

Given two positive integers r and s.

To check whether \small \frac{r}{s} is an integer:

Condition (1):

Every factor of s is also a factor of r.

r \geq s

Let us consider an example:

s = 5^2 \cdot 2\\r = 5^3 \cdot 2^2

\dfrac{r}{s} = \dfrac{5^3\cdot2^2}{5^2\cdot2} = 10

which is an integer.

Actually, in this situation s is a factor of r.

Condition 2:

Every prime factor of <em>s</em> is also a prime factor of <em>r</em>.

(But the powers of prime factors need not be equal as we are not given the conditions related to powers of prime factors.)

Let

r = 2^2\cdot 5\\s =2^4\cdot 5

\dfrac{r}{s} = \dfrac{2^3\cdot5}{2^4\cdot5} = \dfrac{1}{2}

which is not an integer.

So, the answer is:

<em>If statement(1) holds true, it is correct that </em>\small \frac{r}{s}<em> is an integer.</em>

<em>If statement(2) holds true, it is not necessarily correct that </em>\small \frac{r}{s}<em> is an integer.</em>

<em></em>

8 0
3 years ago
I need help :,)
Dmitry_Shevchenko [17]

Answer:

add 17.50 to 8.75 you get 26.25

7 0
2 years ago
Read 2 more answers
Anyone know these, I’m confused?
alisha [4.7K]
Tuv is equal to 127
5 0
3 years ago
Read 2 more answers
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