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Tatiana [17]
3 years ago
9

The shortest side of an isosceles triangle is 2x - 3 inches long. the longer sides are 6 inches longer than the shortest side. t

he perimeter of the triangle is 33 inches. what is the length of each side of the longer sides of the triangle.
PLEASE HEEELP MEE
Mathematics
1 answer:
Zolol [24]3 years ago
8 0
Side 1 = short side = 2x-3
side 2 = longer side = (short side) + 6 = (2x-3)+6 = 2x+3
side 3 = side 2 = 2x+3

Side 2 and side 3 are the longer two congruent sides

Add up the three sides and set them equal to the given perimeter of 33. Solve for x

(side1)+(side2)+(side3) = perimeter
(2x-3)+(2x+3)+(2x+3) = 33
(2x+2x+2x) + (-3+3+3) = 33
6x+3 = 33
6x+3-3 = 33-3
6x = 30
6x/6 = 30/6
x = 5

If x = 5, then the longer sides are 2*x+3 = 2*5+3 = 10+3 = 13 inches each
(note: the short side is 2*x-3=2*5-3=10-3 = 7 inches)

Answer: 13 inches
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Keywords: linear equation, variables

Learn more about linear equations at:

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MArishka [77]
<h3>Answer:  x = 18 (choice B)</h3>

===================================

Work Shown:

Through the inscribed angle theorem, we can say that 2 times the inscribed angle gets us the arc that the inscribed angle cuts off.

2*(inscribed angle) = arc measure

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3 years ago
Read 2 more answers
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