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Alina [70]
3 years ago
15

how much of an 18% salt water mixture should be added to a 15 gallon 2% salt water mixture to achieve a 7% salt water mixture?

Mathematics
1 answer:
Arlecino [84]3 years ago
4 0

If you add <em>x</em> gal of the 18% mixture, each gallon adds 0.18 gal of salt, so <em>x</em> gal would add 0.18<em>x</em> gal of salt.

The 15 gal of 2% salt mixture already contains 0.02 (15 gal) = 0.3 gal of salt.

The total volume of the new mixture would be (15 + <em>x</em>) gal. To achieve a 7% concentration of salt, you would need to add <em>x</em> gal of the 18% mixture such that

(amount of salt) / (total volume) = (0.3 + 0.18<em>x</em>) / (15 + <em>x</em>) = 0.07

Solve for <em>x</em> :

0.3 + 0.18<em>x</em> = 0.07 (15 + <em>x</em>)

0.3 + 0.18<em>x</em> = 1.05 + 0.07<em>x</em>

0.11<em>x</em> = 0.75

<em>x</em> = 0.75 / 0.11 ≈ 6.82 gal

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