Question

A certain group of women has a 0.86​% rate of​ red/green color blindness. If a woman is randomly​ selected, what is the probability that she does not have​ red/green color​ blindness?

Answer 1

Answer:

The probability that a randomly selected woman has red/green color blindness is 0.9914

Step-by-step explanation:

Given that the proportion of women having red/green color blindness is 0.86%

Represent that with p

$p= 0.86\%$

Convert proportion from percentage to decimal;

$p= \frac{0.86}{100}$

$p= 0.0086$

In probability; opposite probabilities add up to 1;

Let the probability that a woman selected have red/green color blindness be represented with q;

$p + q = 1$

Subtract p from both sides

$p - p + q = 1 - p$

$q = 1 - p$

Substitute 0.0086 for p

$q = 1 - 0.0086$

$q = 0.9914$

Hence, the probability that a randomly selected woman has red/green color blindness is 0.9914