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2 years ago

11

What is the area of a circle with the diameter of 10cm ?

2 answers:

8_murik_8 [283]2 years ago

7 0

Answer:

A≈78.54cm² Diamter= 10

Step-by-step explanation:

hope this helps

r-ruslan [8.4K]2 years ago

5 0

Answer:

A=78.54 cm sq

Step-by-step explanation:

Using the formulas

A=πr2

d=2r

Solving for A

A=1

4πd2=1

4·π·102≈78.53982cm²

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I NEED HELP................................................... BRAINLIEST?

Mumz [18]

Remark

Good thing to know. This is a rounding question.

A

Answer A is a bit nasty. I round 5 to the next highest number on the left. That may not be what you have been told to do. Let us round A to 5.7 and see if anything else does this.

B

Answer B rounds to 5.6

C

Answer C rounds to 5.6 as well. 3 is less than 5 so you round down.

D

Answer D rounds to 5.6(.) The zero has no effect on the 6.

Answer

Since there is nothing special about A and nothing else rounds to 5.7, the answer is A. So your rule is when the last number is 5, you round the second last number to one more than it was, regardless of the properties of the second last number.

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2 years ago

1 The ages of three cats are a, a + 4 and 2a - 3.<br> Their total age is 21. Determine a.<br> ?

Nimfa-mama [501]

Answer:

a = 5

Step-by-step explanation:

a +a+4 + 2a-3 = 21

4a +1 =21

4a = 20

a = 5

8 0

3 years ago

A spinner has equal regions numbered 1 through 20. What is the probability that the spinner will stop on an odd number or a mult

klio [65]

Answer:

<em>Probability that the spinner will stop on an odd number or a multiple of 5 is </em><em>0.6</em>

Step-by-step explanation:

Probability = $\frac{Required outcomes}{Total possible outcomes}$

We are given the equal regions numbered from 1 through 20 which means that our total possible outcomes are 20

<em>Total possible outcomes: 20</em>

<em>Outcomes that spinner will stop on an odd number, n(Odd): 10</em>

1, 3, 5, 7, 9, 11, 13, 15, 17, 19

Probability of spinner stoping on Odd number:

P(Odd) = $\frac{n(Odd)}{Total}$ = $\frac{10}{20}$ = $\frac{1}{2}$ = 0.5

Outcomes that spinner will stop on a multiple of 5, n(5): 4

5, 10, 15, 20

Probability of spinner stoping on multiple of 5:

P(5) = $\frac{n(5)}{Total}$ = $\frac{4}{20}$ = $\frac{1}{5}$ = 0.2

Odd numbers which are a multiple of 5 are: 5 and 15

So,

P(Odd and 5) = $\frac{2}{20}=\frac{1}{10}=0.1$

Thus Probability of spinner stopping at odd number or a multiple of 5 becomes:

P(Odd or 5) = P(Odd) + P(5) - P(Odd and 5) = 0.5 + 0.2 - 0.1 = 0.6

7 0

3 years ago

Erry has taken a random sample of students and determined the number of electives that each student in his sample took last year

Cerrena [4.2K]

The mean should be about the same, because the sample is random

6 0

3 years ago

Read 2 more answers

Mr. Clark traveled 456.4 km in 14 days.

xeze [42]

$\qquad \qquad\huge \underline{\boxed{\sf Answer}}$

<h3><u>Distance travelled each day is</u> : </h3>

32.6 km

<h3><u>Explanation</u> : </h3>

Distance travelled in 14 days is : 456.4 km

And if he travels same Distance each day, so let the Distance travelled on each day be x

According to question ~

$\qquad \sf \dashrightarrow \: 14 \times x = 456.4$

$\qquad \sf \dashrightarrow \: x = 456.4 \div 14$

$\qquad \sf \dashrightarrow x = \: 32.6 \: \: km$

So, he travels 32.6 km per day

5 0

2 years ago