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3 years ago

If x is 5, then 6x = 5x 30x 30

Mathematics

1 answer:

Wittaler [7]3 years ago

4 0

Answer:

Step-by-step explanation:

If X is 5, then 6X is equal to 30. You can see to be able to get 30, you have to multiply 6 to X, which in this case is 5. So 6 times 5, you will now get the answer which is 30.

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What is the factor x²+6x+

Lera25 [3.4K]

Answer:

this is what i found

Factor

x out of x 2 . x ⋅ x − 6 x Factor x out of − 6 x . x ⋅ x + x ⋅ − 6 Factor x out of x ⋅ x + x ⋅ − 6 . x ( x − 6 )

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3 years ago

Kirsten has 9 syrup containers from a local cafe. There are 6 milliliters of syrup per container.

ololo11 [35]

Answer: 54 mL

Step-by-step explanation:

Simply do 9(number of containers)*6(Syrup per container) to get 54 mL of syrup.

<em>Hope it helps <3</em>

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3 years ago

Is this true or false?

Mashcka [7]

Answer:

true

Step-by-step explanation:

one tree has 13 apples

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2 years ago

Read 2 more answers

-17=x-15<br> I'm stuck so can someone help

Strike441 [17]

Answer:

-2

Step-by-step explanation:

-2-15

-2 +(-15)

-17

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3 years ago

Read 2 more answers

Considering only the values of β for which sinβtanβsecβcotβ is defined, which of the following expressions is equivalent to sinβ

-Dominant- [34]

Answer:

$\tan(\beta)$

Step-by-step explanation:

For many of these identities, it is helpful to convert everything to sine and cosine, see what cancels, and then work to build out to something. If you have options that you're building toward, aim toward one of them.

${\tan(\theta)}={\dfrac{\sin(\theta)}{\cos(\theta)}$ and ${\sec(\theta)}={\dfrac{1}{\cos(\theta)}$

Recall the following reciprocal identity:

$\cot(\theta)=\dfrac{1}{\tan(\theta)}=\dfrac{1}{ \left ( \dfrac{\sin(\theta)}{\cos(\theta)} \right )} =\dfrac{\cos(\theta)}{\sin(\theta)}$

So, the original expression can be written in terms of only sines and cosines:

$\sin(\beta)\tan(\beta)\sec(\beta)\cot(\beta)$

$\sin(\beta) * \dfrac{\sin(\beta) }{\cos(\beta) } * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) } {\sin(\beta) }$

$\sin(\beta) * \dfrac{\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} {\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}$

$\sin(\beta) *\dfrac{1 }{\cos(\beta) }$

$\dfrac{\sin(\beta)}{\cos(\beta) }$

Working toward one of the answers provided, this is the tangent function.

The one caveat is that the original expression also was undefined for values of beta that caused the sine function to be zero, whereas this simplified function is only undefined for values of beta where the cosine is equal to zero. However, the questions states that we are only considering values for which the original expression is defined, so, excluding those values of beta, the original expression is equivalent to $\tan(\beta)$ .

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2 years ago