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Hatshy [7]
2 years ago
7

What equation do I write for a line that has a y intercept of 2 and is perpendicular to y=2/3x+4?

Mathematics
1 answer:
ser-zykov [4K]2 years ago
5 0

Answer:

y = -3/2x + 2

Step-by-step explanation:

The equation has the format  y = mx + b  where  m  is the slope and  b  is the y-intercept.

The question gives you the y-intercept, so  b = 2.

As for the slope, you need the fact that perpendicular lines have slopes that are opposite ("negative") reciprocals of each other.

The slope of the line given in the question is 2/3.  The opposite reciprocal of 2/3  is  - 3/2.

The equation for the line is  y = -3/2x + 2

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Tanzania [10]

If you wish to<u> mentally estimate</u> the <u>total cost</u> of items, <u>rounding </u>off the items to the<u> nearest half dollar</u>, then you have to consider all five items separately.

Five items cost $1.85, $.98, $3.49, $9.78, and $6.18.

1. $1.85≈$2;

2. $0.98≈$1;

3. $3.49≈$3.50;

4. $9.78≈$10;

5. $6.18≈$6.

Then the total cost is

$2 + $1 + $3.50 + $10 + $6 =$22.50.

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3 years ago
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Imagine you have some workers and some handheld computers that you can use to take inventory at a warehouse. There are diminishi
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Answer:

a. $1.03

b. $0.93

c. 0.98

d. 2 workers

Step-by-step explanation:

a. Given that:

  • 1 computer : 1 worker : inventory 150 items per hour
  • 1 computer : 2 workers : inventory 200 items per hour
  • 1 computer : 3 workers : inventory 220 items per hour
  • 1 computer : 4+ workers : fewer than 235 items per hour
  • Cost: $100 per computer ; $25 per worker

The fixed production factor in the warehouse is the computer used:

-One computer used, but the number of users is varied to inventory a specified number of items.

-The variable production factor is the number of workers assigned per one computer.

#The cost of inventorying a single item by one worker is:

Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_1=\frac{125+30}{150}\\\\\\=1.03

Hence, the cost of inventorying a single item is $1.03

b. Using the information provided above, the cost of inventorying a single item when two workers are assigned is :

Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_2=\frac{125+2\times30}{200}\\\\\\=0.925

Hence, the cost of inventorying a single item is $0.93

c.Using the information provided above, the cost of inventorying a single item when three workers are assigned is :

Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_3=\frac{125+3\times30}{220}\\\\\\=0.98

Hence, the cost of inventorying a single item is $0.98

d. To determine the most cost-effective job assignment, we calculate the cost of 4+ workers.

Take any number less than 235(say 234) as the inventory units:

Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_4=\frac{125+4\times30}{234}\\\\\\=1.05

From our calculations, it's clear that two workers per computer costs the least amount($0.93) per unit item. Hence, it is best to assign two workers per computer.

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Answer:

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V = (7/3)³ × 756

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