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Nadya [2.5K]
3 years ago
15

Please help me figure out this problem?

Mathematics
1 answer:
Sedaia [141]3 years ago
4 0

Answer:

the answer is

\sqrt{113in}

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Polynomial Basics
Rzqust [24]
Exponential is the answer okau
5 0
2 years ago
A student multiplies (4+5i) (3-2i) incorrectly and obtains 12-10i what is the students mistakes
Rufina [12.5K]

Answer:

1. In the multiplication of the imaginary parts, the student forgot to square of i. OR

2. The student has only multiplied the real parts and the imaginary parts.

Correct value =22+7i.

Step-by-step explanation:

The given expression is

(4+5i)(3-2i)

A student multiplies (4+5i) (3-2i) incorrectly and obtains 12-10i.

Student's mistake can be either 1 or second:

1. In the multiplication of the imaginary parts, the student forgot to square of i.

2. The student has only multiplied the real parts and the imaginary parts.

(4+5i)(3-2i)=4\times 3+5\times (-2)i=12-10i

Which is not correct. The correct steps are shown below.

Using distributive property, we get

4(3-2i)+5i(3-2i)

4(3)+4(-2i)+5i(3)+5i(-2i)

12-8i+15i-10i^2

12+7i-10(-1)       [\because i^2=-1]

12+7i+10

22+7i

Therefore, the correct value of (4+5i)(3-2i) is 22+7i.

4 0
3 years ago
Watermelons cost $0.35 per pound. Joseph’s watermelon costs between $4.20 and $5.25. Which compound inequality correctly represe
Ahat [919]
Working is attached :)

4 0
3 years ago
Find the value of each measure.
zloy xaker [14]

The two congruent base angles tell us that this is an isosceles triangle, meaning the triangle has two congruent sides. Therefore, we can set these two expressions equal to each other and solve from there.

15x + 7 = 23x - 17

7 = 8x - 17

8x = 24

x = 3

Side = 15(3) + 7 = 45 + 7 = 52

Hope this helps!

4 0
3 years ago
Is it possible that the image of a point after a reflection could be the same point as the preimage?
Vera_Pavlovna [14]
Yes, it is possible. For example, let's say that point A is (0,4) and there's a reflection over the y-axis, then point A would still be (0,4).
3 0
3 years ago
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