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luda_lava [24]
3 years ago
14

The sears tower in chicago is 1450 feet high. A model of the tower is 24 inches tall. What is the ratio of the height of the mod

el to the height of the actual sears tower.
Mathematics
2 answers:
Dominik [7]3 years ago
8 0

Answer:

\frac{1}{725}

The sear tower is 725 times higher than the sears tower model

Step-by-step explanation:

we know that

The ratio of the height of the model to the height of the actual sears tower is equal to the scale factor

Let

z------> the scale factor

x-------> the height of the model

y-------> the height of the actual

so

z=\frac{x}{y}

we have

x=24\ in

y=1,450\ ft

substitute

z=\frac{24}{1,450}\frac{in}{ft}

simplify

z=\frac{12}{725}\frac{in}{ft}

Remember that

1\ ft=12\ in

so

\frac{12}{725}\frac{in}{ft}=\frac{1}{725}\frac{ft}{ft}

Gemiola [76]3 years ago
8 0
The sear tower is 725 times higher than the sears tower model
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P(O and O)= 0.36 X 0.36 =0.1296

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Answer:

Step-by-step explanation:

Volumes of two spheres A and B = 648 cm³ and 1029 cm³

Things to remember:

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2). Area scale factor = \frac{(r_1)^2}{(r_2)^2}

3). Volume scale factor = \frac{(r_1)^3}{(r_2)^3}

Volume scale factor Or Volume ratio = \frac{V_A}{V_B}

                         \frac{(r_1)^3}{(r_2)^3}= \frac{648}{1029}

                         \frac{r_1}{r_2}=\sqrt[3]{\frac{648}{1029} }

                         \frac{r_1}{r_2}=\frac{6(\sqrt[3]{3})}{7(\sqrt[3]{3})}

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