Hello from MrBillDoesMath!
Answer:
8(v+3) ( -1/2 (sqrt(14) - 4 v) (4 v + sqrt(14)) )
Discussion:
Given
64v^3 + 192v^2 - 56 v - 168
Factor 64v^2 from the first two terms. Factor 56 from the last two terms:
64v^2(v+3) - 56(v + 3) => factor (v+3) from both terms
(v+3) (64v^2 - 56) => factor 8 from both terms in the right ()
8(v+3)(8v^2-7) => factor 8y^2-7
8(v+3) ( -1/2 (sqrt(14) - 4 v) (4 v + sqrt(14)) )
Thank you,
MrB
Answer:
50
Step-by-step explanation:
Sum Even numbers
n = 50
d = 2
a1 = 2
The last number is
an = a1 + (n-1)d
an = 2 + (50 - 1)*2
an = 2 + 49 * 2
an = 2 + 98
an = 100
Sum of the even numbers
Sum = (a1 + a50)*n/ 2
Sum = (2 + 100)*50/2
sum = 102 * 25
sum = 2550
Sum of the first 50 odd numbers
a1 = 1
n = 50
d = 2
l = ?
Find l
l = a1 + (n - 1)*2
l = 1 + 49*2
l = 99
Sum
Sum = (1 + 99)*50/2
Sum = 2500
The difference and answer is 2550 - 2500 = 50
15 electricians worked for 24 days to the whole job, now, there are 15 of them, so on any given day, each electrician worked one whole day, in 24 days, that one electrician worked 24 days total.
now, there were 15 electricians on any given day though, since each one of them worked the whole day that one day, so the "days work worth" on a day is 15, so the house gets 15days worth of work because of that.
so how many "days worth" did all 15 do on the 24 days, well, 15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15, namely 15 * 24, or 360 days worth of work.
since it takes 360 days worth of work to do the whole wiring, in how many days would 18 electricians do it? 360/18.
Answer:
15 minutes
Step-by-step explanation:
Their rate together is 1/6 floor per minute.
Her rate alone is 1/10 floor per minute.
His rate is the difference of these:
1/6 - 1/10 = 5/30 -3/30 = 2/30 = 1/15 . . . . floor per minute
It would take Jacob 15 minutes to do it alone.
