3 years ago

The elves made a total of 739 dolls on Monday. They made 9 different types of dolls. How many of each doll did they make?

Mathematics

2 answers:

castortr0y [4]3 years ago

8 0

You would divide 739 by 9

chubhunter [2.5K]3 years ago

3 0

THEY MAKE 81 DOLLS of each type

739
------
9
=====
81.11

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Can anyone help me with this problem? If you can include the steps, please do! Thanks :)

8090 [49]

Answer:1=70 2=65 3=95

Step-by-step explanation:

Angles in a triangle add up to 180°

180-45=135-65=70

1=70°

Angles on a straight line add up to 180°

180-45=135-70=65

2=65°

Angles in a triangle add up to 180°

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3 0

4 years ago

Each game costs $1.25 and each ride costs $2.75. A boy spent $20.25 all together at the carnival and the number of rides he went

a_sh-v [17]

Answer:

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Step-by-step explanation:

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3 years ago

In the diagram, what is the value of x? A. 144° B. 28° C. 5° D. 36°

In-s [12.5K]

X+4x = 180
5x = 180
x =180/5
x = 36

answer
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4 0

3 years ago

For the monthly rainfall data set of 7 cm, 3 cm, 10 cm, 7 cm, 12 cm, 10 cm, 8 cm, and 7 cm calculate the mean. * what is the mea

timama [110]

The mean would be 8 since you would have to add all of them up which would give you 64 and then divide by the amount of numbers their are which is 8 so 64/8 = 8

5 0

3 years ago

If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.

Lelechka [254]

Answer:

$\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }$

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

$f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)$

So we can say that

$a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}$

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

$(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab$

and we can notice that

$a^2+b^2=(a+b)^2-2ab$ so

$(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab$

it comes

$x^2-5*\dfrac{4}{3}x+6(\dfrac{4}{3})^2+\dfrac{5}{3}$

multiply by 3

$3x^2-20x+2*16+5=3x^2-20x+37$

4 0

3 years ago