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3 years ago

The volume of a cube is 64 centimeters. What is the surface area of the cube?

Mathematics

1 answer:

Andrews [41]3 years ago

4 0

Answer:

Step-by-step explanation:

16 $cm^{2}$

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Subtract 2+ 3a2 -12ab +4b2 from 1+ 8a2+16ab +2b2

Anvisha [2.4K]

The answer of the following subtraction is 5 $a^{2} -2b^{2} +28ab$

Step-by-step explanation:

As per the question the equation will be

$(1+8a^{2}+16ab+2b^{2} ) - (2+3a^{2} -12ab+4b^{2} )$

To find the subtraction,

The steps are as follow

= $1+8a^{2} +16ab+2b^{2} - 2 -3a^{2} +12ab-4b^{2}$

=1-2 + $8a^{2} -3a^{2} +2b^{2} -4b^{2} +16ab+12ab$

[ we took the variables with same power together]

=5 $a^{2} -2b^{2} +28ab$

Hope it helps you.

3 0

3 years ago

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What is the turning point of the graph of f(x) = |x+3| -2?

Tema [17]

Answer:

(-2,-3)

Step-by-step explanation:

I took the test and got it wrong at first but seen the correct answer when I looked at my results.

8 0

3 years ago

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A 13-ft ladder is leaning against a house when its base starts to slide away. By the time the base is 5 ft from the house, the

lord [1]

Answer:

a. -5 ft per sec

b. 59.5 ft² per sec

Step-by-step explanation:

a. Suppose l represents the ladder, x represents the height of the top of ladder from the base of house and y represents the distance of base of ladder from the base of house.

By the Pythagoras theorem,

$l^2 = x^2 + y^2------(1)$

Differentiating with respect to t ( time ),

$2l\frac{dl}{dt} = 2x \frac{dx}{dt}+2y\frac{dy}{dt}$

But, height of ladder, l = 13 ft = constant,

$\implies \frac{dl}{dt}=0$

$\implies 0= 2x \frac{dx}{dt}+2y\frac{dy}{dt}-----(2)$

We have,

y = 5, $\frac{dy}{dt}=12\text{ ft per sec}$ ,

Again by equation (1),

$13^2 = x^2 + 5^2\implies 169 = x^2 + 25\implies 169 - 25 = x^2\implies 144 = x^2\implies x = 12\text{ ft}$

From equation (2),

$0 = 2(12) \frac{dx}{dt} + 2(12)(5)$

$0= 24\frac{dx}{dt}+120$

$-120 =24\frac{dx}{dt}$

$\implies \frac{dx}{dt}=-\frac{120}{24}=-5\text{ ft per sec}$

Hence, the rate of change of the height of the top of the ladder is -5 ft per sec.

b. Now area of the triangle = 1/2 × base × height

$\implies A = \frac{1}{2}\times y\times x$

Differentiating with r. t. t,

$\frac{dA}{dt}=\frac{1}{2}(y\frac{dx}{dt}+x\frac{dy}{dt})$

$= \frac{1}{2}(5(-5) + 12(12))$

$=\frac{1}{2}(-25 + 144)$

$=\frac{119}{2}$

= 59.5 ft² per sec

Hence, area of the triangle is changing with the rate of 59.5 ft per sec.

7 0

4 years ago

Given f(x) = 5x^6 what is the domain?5 < X ≤ 6x ≥ 0X ≤ Oall real numbers

Vilka [71]

The domain is the set of all possible x-values which will make the function "work", and will output real y-values

$\begin{gathered} \text{Let} \\ f(x)=5x^6 \\ \end{gathered}$

there is not a value for x, that makes the function does not "work", so x can take any value, in other words all real numbers

so, the answer is all real numbers

6 0

1 year ago

Question 1 (1 point)

defon

Honey you’re smart you can figure this out you’re gonna do great things make,

4 0

3 years ago

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