Answer:
2082.12 was the total invested
Step-by-step explanation:
Let x represent the amount invested at 14%. Then the amount invested at 12% was (x-580). The total accumulated amount was ...
112%(x -580) +114%(x) = 2358.60
2.26x -649.60 = 2358.60
2.26x = 3008.20 . . . add 649.60
x = 1331.06 . . . . . . divide by 2.26
x -580 = 751.06
The total invested was 1331.06 +751.06 = 2082.12 cedis.
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<em>Check</em>
The investment at 12% was 751.06, so the accumulated amount of that investment was 751.06×1.12 = 841.19.
The investment at 14% was 1331.06, so the accumulated amount of that investment as 1331.06×1.14 = 1517.41.
The accumulated total amount was 841.19 +1517.41 = 2358.60.
Answer:
Answer Below....
Step-by-step explanation:
Answer:
Her sign is in error. The answer is -3/8.
Step-by-step explanation:
Nancy's answer has the correct magnitude. It is obtained by multiplying 1/4 by -3/2. However, the sign of that product will be negative. Nancy has reported a positive answer, so <em>it is incorrect</em>.
Answer: The length is 12 feet and the width is 4 feet.
Step-by-step explanation:
Let L represent the length of the bedroom closet.
Let W represent the width of the bedroom closet..
The formula for determining the perimeter of a rectangle is expressed as
Perimeter = 2(L + W)
The perimeter of the bedroom closet is 32 ft. This means that
2(L + W) = 32
Dividing through by 2, it becomes
L + W = 32/2
L + W = 16
The area of the bedroom closet is 48 ft². This means that
LW = 48 - - - - - - - -- - - - - - 1
Substituting L = 16 - W into equation 1, it becomes
W(16 - W) = 48
16W - W² = 48
W² - 16W + 48 = 0
W² - 12W - 4W + 48 = 0
W(W - 12) - 4(W - 12) = 0
W - 12 = 0 or W - 4 = 0
W = 12 or W = 4
L = 16 - 4 = 12
Answer:
3 cm
Step-by-step explanation:
When we enlarge or shrink an object, we perform a dilation. A dilation preserves the relationship between sides and the exact angle measure. This means the original and the enlargement are proportional and any missing lengths can be found through a proportion.
A proportion is an equation where two ratios or fractions are equal. The ratios or fractions compare like quantities. For example, we will compare height over length of the original rectangle to an equal ratio of height to length of the enlargement. Since we do not know height of the enlargement, we will use a variable to write:
I can now cross-multiply by multiplying numerator and denominator from each ratio.
I now solve for h by dividing by 9.
The new height is 3 cm.
