This means 21g is 100-16%=84%.
21x0.16=3.36
21+3.36=24.36
Answer: y = 16.5
Step-by-step explanation:
We would apply Pythagoras theorem which is expressed as
Hypotenuse² = opposite side² + adjacent side²
Considering triangle BCD,
BD² = 14² - 8²
BD² ° 196 - 64 = 132
BD = √132
Considering triangle ABD,
AB² = BD² + y²
AB² = (√132)² + y²
AB² = 132 + y²- - - - - - - - - - 1
Considering triangle ABC,
(8 + y)² = AB² + BC²
(8 + y)² = AB² + 14²
(8 + y)² = AB² + 196
AB² = (8 + y)² - 196- - - - - - - -2
Substituting equation 1 into equation 2, it becomes
132 + y² = (8 + y)² - 196
y² - (8 + y)² = - 196 - 132
y² - (64 + 16y + y²) = - 328
y² - 64 - 16y - y2 = - 328
- 16y = - 328 + 64
- 16y = - 264
y = - 264/- 16
y = 16.5
Answer:
2
Step-by-step explanation:
Plug 4 in for d and 3 in for c
5d-2/3c
5(4)-2/3(3)
Multiply in the numerator and the denominator
20-2/9
Subtract in the numerator
18/9
2
Hope this helps! :)
Hello There!
100% - 80% = 20%
20% = 3
Therefore, 10% = 1.5
100% = 10 x 10%
100% = 10 x 1.5
100% = 15.
There were 15 questions.
Hope This Helps You!
Good Luck :)
- Hannah ❤
Answer:
With replacing
Assuming replacing for the first selection we have a total of 52 cards and 4 possible options and for the second selection since we put again the card again in the deck we have the same probability of selection for a jack. We can assume independence between the events and we got:
Without replacing
Assuming replacing for the first selection we have a total of 52 cards and 4 possible options and for the second selection since we don't put again the card again in the deck so we will have 3 possible options and 51 total cards. We can assume independence between the events and we got:
Step-by-step explanation:
For this case we assume that we have a standard deck of 52 cards
And we have 4 Jacks on the deck
With replacing
Assuming replacing for the first selection we have a total of 52 cards and 4 possible options and for the second selection since we put again the card again in the deck we have the same probability of selection for a jack. We can assume independence between the events and we got:
Without replacing
Assuming replacing for the first selection we have a total of 52 cards and 4 possible options and for the second selection since we don't put again the card again in the deck so we will have 3 possible options and 51 total cards. We can assume independence between the events and we got: