I found this!!!!
The scientist can use these two measurements to calculate the distance between the Sun and the shooting star by applying one of the trigonometric functions: Cosine of an angle.
- The scientist can substitute these measurements into cos\alpha=\frac{adjacent}{hypotenuse}cosα=
hypotenuse
adjacent
and solve for the distance between the Sun and the shooting star (which would be the hypotenuse of the righ triangle).
Step-by-step explanation:
You can observe in the figure attached that "AC" is the distance between the Sun and the shooting star.
Knowing the distance between the Earth and the Sun "y" and the angle x°, the scientist can use only these two measurements to calculate the distance between the Sun and the shooting star by applying one of the trigonometric functions: Cosine of an angle.
This is:
cos\alpha=\frac{adjacent}{hypotenuse}cosα=
hypotenuse
adjacent
In this case:
\begin{gathered}\alpha=x\°\\\\adjacent=BC=y\\\\hypotenuse=AC\end{gathered}
α=x\°
adjacent=BC=y
hypotenuse=AC
Therefore, the scientist can substitute these measurements into cos\alpha=\frac{adjacent}{hypotenuse}cosα=
hypotenuse
adjacent
, and solve for the distance between the Sun and the shooting star "AC":
cos(x\°)=\frac{y}{AC}cos(x\°)=
AC
y
AC=\frac{y}{cos(x\°)}AC=
cos(x\°)
y
Answer:
7
Step-by-step explanation:
Put the numbers in order from least to greatest:
5, 0, |-1|, |4|, -2
I believe that the answer is B. 62°
Correct Question: If m∠JKM = 43, m∠MKL = (8x - 20), and m∠JKL = (10x - 11), find each measure.
1. x = ?
2. m∠MKL = ?
3. m∠JKL = ?
Answer/Step-by-step explanation:
Given:
m<JKM = 43,
m<MKL = (8x - 20),
m<JKL = (10x - 11).
Required:
1. Value of x
2. m<MKL
3. m<JKL
Solution:
1. Value of x:
m<JKL = m<MKL + m<JKM (angle addition postulate)
Therefore:
Solve for x
Subtract 8x from both sides
Add 11 to both sides
Divide both sides by 2
2. m<MKL = 8x - 20
Plug in the value of x
m<MKL = 8(17) - 20 = 136 - 20 = 116°
3. m<JKL = 10x - 11
m<JKL = 10(17) - 11 = 170 - 11 = 159°
42,500x0.09 should get you your commission
