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lys-0071 [83]
3 years ago
7

How many password arrangements are possible on a standard keyboard. Passwords must taai daadas long,pro

Mathematics
1 answer:
Irina-Kira [14]3 years ago
7 0

Answer:

the answer will be the first option

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I'm stuck on this one:( help me please ​
ZanzabumX [31]

Answer:

Step-by-step explanation:

f-1(x) is the inverse of f(x)

to find the inverse let’s set the equation up like this

y = 4x -2

now we’ll switch x and y

x = 4y -2

and solve for y

x + 2 = 4y

x/4 + 2/4 = y

the inverse is

y = x/4 + 1/2

this equation is written in y = mx + b form

where b = y intercept

so the y intercept is 1/2

6 0
3 years ago
What is ( 12 ) divided by 3??
GarryVolchara [31]
12 divides by 3 is equal to 4
4 0
4 years ago
Solve the equation 2/3x-2=7
Dovator [93]

Answer: x = 27/2

Step-by-step explanation:

2/3x-2=7

2/3x=9

2/3x=27/3

2/3x(3/2)=27/3(3/2)

x=81/6

x=27/2

4 0
4 years ago
Read 2 more answers
Determine the numerical value of the following expression without the use of a calculator:
pashok25 [27]

The numerical value if the expression is 0

The expression to be solved is

log ( log ( 3 )- log ( 2 ) - (\frac{\sqrt{3}-2sin ( \frac{pi}{3} ) }{pi^{3} +1 } +1)) - log ( 2 ) log ( 3)   } + ( -1 )^{100}

<h3>How to solve the given expression</h3>

sin ( pi/3 ) = \frac{\sqrt{3} }{2}

2sin ( pi/3 ) = 2 *  \frac{\sqrt{3} }{2} = \sqrt{3}

log ( log ( 3 )(log ( 2 )  (\frac{\sqrt{3}-2sin ( \frac{pi}{3} ) }{pi^{3} +1 } +1)) - log ( 2 ) log ( 3)   } + ( -1 )^{100})\\log ( log ( 3 ) log ( 2 )  (\frac{\sqrt{3}- \sqrt{3}  }{pi^{3} +1 } +1)) - log ( 2 ) log ( 3)   } + ( -1 )^{100})\\log ( log ( 3 ) log ( 2 ) (\frac{0  }{pi^{3} +1 } +1)) - log ( 2 ) log ( 3)   } + ( -1 )^{100})

log ( log ( 3 ) log ( 2 )  (0 +1 ) - log ( 2 ) log ( 3)   } + ( -1 )^{100})\\log ( log ( 3 ) log ( 2 )  - log ( 2 ) log ( 3) + ( -1 )^{100})\\log (0 + ( -1 )^{100})

since 100 is even

( -1 )^{100} = 1

therefore

log (0 + ( -1 )^{100})\\log (0 + 1)\\log 1\\0

Read more on logarithm here: brainly.com/question/247340

#SPJ1

The complete question is attached

6 0
2 years ago
Read 2 more answers
Evaluate the question
Vesna [10]

Answer:

we conclude that:

\frac{2^{-\frac{4}{3}}}{54^{-\frac{4}{3}}}=81

Step-by-step explanation:

Given the expression

\frac{2^{-\frac{4}{3}}}{54^{-\frac{4}{3}}}

\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}\:=\:x^{a-b}

\frac{2^{-\frac{4}{3}}}{54^{-\frac{4}{3}}}=\left(\frac{2}{54}\right)^{-\frac{4}{3}}

\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}

         =\frac{1}{\left(\frac{2}{54}\right)^{\frac{4}{3}}}

        =\left(\frac{1}{27}\right)^{-\frac{4}{3}}

\mathrm{Apply\:exponent\:rule}:\quad \left(\frac{a}{b}\right)^c=\frac{a^c}{b^c}

        =\frac{1}{\frac{1^{\frac{4}{3}}}{27^{\frac{4}{3}}}}

         =\frac{1}{\frac{1^{\frac{4}{3}}}{81}}      ∵ 27^{\frac{4}{3}}=81

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{1}{\frac{b}{c}}=\frac{c}{b}

         =\frac{81}{1^{\frac{1}{3}}}              

\mathrm{Apply\:rule}\:1^a=1

         =\frac{81}{1}

          =81

Therefore, we conclude that:

\frac{2^{-\frac{4}{3}}}{54^{-\frac{4}{3}}}=81

                         

7 0
3 years ago
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