Answer:
Yes. The data provide enough evidence to support the claim that the mean weight of one-year-old boys is greater than 25 pounds.
P-value=P(t>2.84)=0.0024
Step-by-step explanation:
Hypothesis test on the population mean.
The claim is that the mean weight of one-year-old boys is greater than 25 pounds.
Then, the null and alternative hypothesis are:

The significance level is α=0.05.
The sample size is n=354. The sample mean is 25.8 pounds and the sample standard deviation is 5.3 pounds. As the population standard deviation is estimated from the sample standard deviation, we will use a t-statistic.
The degrees of freedom are:

The t-statistic is:

For a right tailed test and 353 degrees of freedom, the P-value is:

As the P-value is smaller than the significance level, the effect is significant and the null hypothesis is rejected.
There is enough evidence to support the claim that the mean weight of one-year-old boys is greater than 25 pounds.
I would say B is the answer
Answer:
No.
Step-by-step explanation:
1. Subsutute p/q with the numbers given, p = -2 and q = 5.
-2 / 5.
2. Divide 2/5 and -2/5 and compare.
2 / 5 = 0.40
-2 / 5 = -0.40
-0.40 < 0.40
If they are not =, then they are <u>NOT</u> equivalent.
Which means, they are Not equivalent.
We actually need the choices but oh well, we can simpify and hopefuly it is one of the choices
remember the distributive property
a(b+c)=ab+ac
so
7(p+2n)+n
distribute first
7(p)+7(2n)+n
7p+14n+n
7p+15n is an equivilent expression
First, change everything into minutes.
12 noon is 12 by 60 which = 720 minutes.
9am is 9 by 12 which = 540 minutes.
X is now your number of minutes before noon.So noon - x is the next step:
720 - x
20 minutes ago it was 720 - x - 20
720 - x - 20= 540 + 3x (3x because you're looking for 3 times as many minutes)
720 - 20 - 540=4x (you combine all the like numbers and variables)
160 = 4x
160/4= x
40 = x
Your answer is 40 minutes
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