Answer:
The number of times members and non-members will have to rent a boat in order to pay the same amount=20
Step-by-step explanation:
We can have two expressions to show the total cost paid by a member and non-member;
Total cost by member=Cost per summer season+cost per number of times they rent a boat×number of times they rent a boat
where;
Cost per summer season=$105
Cost per number of times they rent a boat=$9.50
Number of times they rent a boat=n
Replacing;
Total cost by a member=105+(9.5×n)=9.5 n+105......equation 1
Total cost by a non-member=Cost per number of times they rent a boat×number of times they rent a boat
where;
Cost per number of times they rent a boat=$14.75
Number of times they rent a boat=n
Replacing;
Total cost by a non-member=(14.75×n)=14.75 n......equation 2
To calculate the number of times they would have to rent a boat in order to pay the same amount, we equate equation 1 to equation 2
9.5 n+105=14.75 n
14.75 n-9.5 n=105
5.25 n=105
n=105/5.25
n=20
The number of times members and non-members will have to rent a boat in order to pay the same amount=20
180 and 20 other words eeeee
Answer:
80 893 720
Step-by-step explanation:
hope dis helps!!!!
20 liters I looked up the answer and did research on how to find it.
Answer:
x = price of balcony tickets = $7
y = price of orchestra tickets = $21
Step-by-step explanation:
Let
x = price of balcony tickets
y = price of orchestra tickets
y = 3x (1)
148y + 76x = 3,640 (2)
Substitute y = 3x into (2)
148y + 76x = 3,640 (2)
148(3x) + 76x = 3,640
444x + 76x = 3,640
520x = 3,640
x = 3,640/520
x = 7
Substitute x = 7 into (1)
y = 3x (1)
y = 3(7)
y = 21
x = price of balcony tickets = $7
y = price of orchestra tickets = $21
