Answer:
Step-by-step explanation:
When Riko left his house, Yuto was 5.25 miles along the path.
Average speed of Riko = 0.35 miles per minute
Average speed of Yuto = 0.25 miles per minute
First we will calculate the time in which Riko will catch Yuto on the track.
Relative velocity of Riko as compared to Yuto will be = velocity of Riko - velocity of Yuto
= 0.35 - 0.25
= 0.10 miles per minute
Now we this relative velocity tells that Riko is moving and Yuto is in static position.
By the formula,
Average speed = 
0.10 = 
t = 
t = 52.5 minutes
Now we know that Rico will catch Yuto in 52.5 minutes. Before this time he will be behind Yuto.
So duration of time in which Rico is behind Yuto will be 0 ≤ t ≤ 52.5
Here time can not be less than zero because time can not be with negative notation. It will always start from 0.
Step-by-step explanation:
c=5/9(f-32) can also be written as c = 5(f - 32)/9.
Multiply each side by 9.
That gives us 9c = 5(f - 32).
Apply distributive rule on the right side.
9c = 5f - 160
Add 160 to the left side.
9c + 160 = 5f
Lastly, divide both sides 5.
(9c + 160)/5 = f
The answer is 7.76 because the fraction written as a decimal would be 7.76 and not any of the other choices they want you to find which number is equal to the fraction number
The given equation is:
t = 7 + 5q
where:
t is the total number of points
q is the questions answered correctly
We are given that the total of correct answers is 6 and we want to find the total number of points. Therefore, all we have to do is substitute with the number of answers in the given equation to get the total points as follows:
t = 7 + 5q
t = 7 + 5(6)
t = 7 + 30
t = 37 points
Answer:
El espesor de un chip es de 0.12mm
Y el diámetro de un átomo de cobre, mide aprox:
0.00000000133 m
Queremos saber cuantos átomos deberemos alinear de tal forma que la "cadena" de átomos de cobre mida 0.12mm
Eso es equivalente a ver cuantas veces entra 0.00000000133 m en 0.12mm
Primero, escribamos ambos valores en las mismas unidades, sabiendo que:
1m = 1000mm
Podemos reescribir:
0.00000000133m = 0.00000000133*(1000 mm) = 0.00000133mm
Entonces tenemos que ver cuantas veces entra 0.00000133mm en 0.12mm
Esto sera igual al cociente entre 0.12mm y 0.00000133mm, esto es:
N = (0.12mm)/(0.00000133mm) = 90,225.6
Redondeamos al próximo número entero:
N = 90,226
Esa es la cantidad de átomos que se necesitan.
