(A) The print area is 4/10 × 100% = 40% of the total, so the ad area is ...
... 100% - 40% = 60% of the print area
(B) News : Ads = (40%) : (60%) = 2 : 3
Answer: 1. C, 2. B, 3. C, 4. C, 5. B, 6. B
Answer:
m
Step-by-step explanation:
Let
Bas length of box=b
Height of box=h
Material used in constructing of box=36 square m
We have to find the height h and base length b of the box to maximize the volume of box.
Surface area of box=




Volume of box, V=
Substitute the values


Differentiate w. r.t b







The negative value of b is not possible because length cannot be negative.
Again differentiate w.r.t b

At

Hence, the volume of box is maximum at
.




m
cos 2 x = cos² x - sin² x = 1 - sin² x - sin² x = 1 - 2 sin² x.
Answer: A ) 1 - sin² x and D ) cos² x - sin² x
Thank you.
2 over 3 you're welcome :)